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3 years ago

8

The segments shown below could form a triangle?

2 answers:

Rainbow [258]3 years ago

8 0

The answer is false That should be The right answer

Leni [432]3 years ago

3 0

Answer:

<em>Option B; False</em>

Step-by-step explanation:

Consider a Triangle Inequality to prove that these segments could form a triangle;

$| a - b | < c < a + b,\\| c - a | < b < a + c,\\| c - b | < a < b + c, Considering - a - segment AC ( 8 units ) - b - BC ( 7 units ), - c - BC ( 15 units )\\\\| 8 - 7 | < 15 < 8 + 7,\\1 < 15 < 15, Now 15 is not < 15, it is =, thus ;\\Solution ; False$

<em>These segments could not form a triangle</em>

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[ Let f ( x ) ] = [ 3 x 2 + 2 x ] , [ g ( x ) ] = [ 3 x + 9 ] , [ h ( x ) ] = [ 12 + x ] , [ What is f ( g ( 3 ) ) ? ] [ Let f (

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Answer:

The value of f(g(3) = 1,008

Step-by-step explanation:

<u>Step:-1</u>

Given f(x) = $3 x ^ 2 + 2 x$

and g(x) = 3x+9

h(x) = 12+x

Given g(x) = 3x+9

put x =3

g(3) = 3(3)+9

<u> g(3) = 18</u>

<u>Step :-(2)</u>

f(g(3)) = f(18)

f(g(3) = 3(18)^2 +2(18) (since f(x) = $3 x ^ 2 + 2 x$ )

= 1,008

<u>Final answer</u>:-

The value of f(g(3) = 1,008

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