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Stels [109]
2 years ago
8

The segments shown below could form a triangle?

Mathematics
2 answers:
Rainbow [258]2 years ago
8 0
The answer is false That should be The right answer
Leni [432]2 years ago
3 0

Answer:

<em>Option B; False</em>

Step-by-step explanation:

Consider a Triangle Inequality to prove that these segments could form a triangle;

| a - b | < c < a + b,\\| c - a | < b < a + c,\\| c - b | < a < b + c, Considering - a - segment AC ( 8 units ) - b - BC ( 7 units ), -  c - BC ( 15 units )\\\\| 8 - 7 | < 15 < 8 + 7,\\1 < 15 < 15, Now 15 is not < 15, it is =, thus ;\\Solution ; False

<em>These segments could not form a triangle</em>

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Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

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Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

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The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

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