The segments shown below could form a triangle?
2 answers:
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The complete question in the attached figure
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>
we know that
the equation of a parabola is
y=a(x-h)²+k
where
(h,k) is the vertex --------> (h,k)--------> (-1,2)
so
y=a(x+1)²+2
point (2,20)
for x=2
y=20
20=a(2+1)²+2--------> 20=a*9+2--------> 9*a=18---------> a=2
the equation of a parabola is
y=a(x+1)²+2-------> y=2(x+1)²+2
therefore
the answer is the option
<span>C) f(x) = 2(x + 1)2 + 2</span>