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SVEN [57.7K]
3 years ago
10

In the Programming Process which of the following is not involved in defining what the program is to do:_____________ Group of a

nswer choices
a. Compile code
b. Purpose
c. Output
d. Input
e. Process
Computers and Technology
1 answer:
Andrew [12]3 years ago
5 0

Answer:

a. Compile code

Explanation:

In programming process, the following are important in defining what a program is to do;

i. Purpose: The first step in writing a program is describing the purpose of the program. This includes the aim, objective and the scope of the program.  The purpose of a program should be defined in the program.

ii. Input: It is also important to specify inputs for your program. Inputs are basically data supplied to the program in order to perform a task. Valid inputs are defined in the program.

iii. Output: Many times, when inputs are supplied to a program the resulting effects are shown in the outputs. The way the output will be is defined in the program.

iv. Process: This involves the method by which inputs are being mapped into outputs. The process implements the functionality of the program by converting inputs into their corresponding outputs. The process is defined in the program.

Compile code is not a requirement in defining what a program is to do. It just allows the source code of the program to be converted into a language that the machine understands.

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Equality and Relational Operators

For the statement to return false, you can simply use the "not equal to" equality operation. The full symbol of this operation is '!=', disregarding the quotes.

<u>Examples:</u>

  • [1 != 1]  would produce FALSE. Translation: 1 <u>does not equal</u> 1?
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CONCLUSION: Use "!=".

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One factor affecting digital camera quality is the number of pixels, measured in ____, used to store the data for each image.
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Write the definition of a function named swapints that is passed two int reference parameters. The function returns nothing but
Alja [10]

Answer:

void swapints(int *j,int *k)//Function definition.

{

   *j=*j+*k-(*k=*j); //value swapping.

}

swapints(&j,&k);//call the function.

Explanation:

  • The above function definition takes the address of j and k variables which is stored on the pointer variable j and k.
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  • But when the user prints the value of the j and k variable, then he gets the swapping value of the j and k variable.
  • The user needs to know that the "int j" is a normal variable, but "int *j" is a pointer variable that is used to take the address of j variable.
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Answer:

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2 years ago
Write a program that prompts the user to enter a month (1-12) and year, then displays the number of days in the month. For examp
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Answer:

In Java

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

    int mnth, yr;

 Scanner input = new Scanner(System.in);

 System.out.print("Month: ");  mnth = input.nextInt();

 System.out.print("Year: ");  yr = input.nextInt();

 boolean lpYear = (yr % 4 == 0 && yr % 100 != 0) || (yr % 400 == 0);

 if(mnth == 1 || mnth == 3 || mnth == 5 || mnth== 7 || mnth == 8 || mnth == 10 || mnth == 12){

     System.out.print("31 days");  }

 else if(mnth == 2){

     System.out.print(((lpYear) ? "29 days" : "28 days"));  }

else if(mnth == 9 || mnth == 6 || mnth == 4 || mnth== 11){

     System.out.print("30 days");  }

 else{      System.out.print("Invalid");  }

}

}

Explanation:

See attachment for complete program where comments were used as explanation.

Download txt
3 0
3 years ago
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