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3 years ago

In creating a professional action plan it's important to

1 answer:

5 0

Whenever creating a professional action plan, it might be easier to do an "if...then..." plan, or just a daily plan, like this:

Monday:
Kitchen:
Do dishes
Sweep floor
Wipe counters

Bedroom:
do laundry etc,

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If you see ________________________ in a cell, it means the column is not wide enough to display the cell content. Select one: a

snow_lady [41]

the answer is c, ######

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3 years ago

Which are technical and visual demands that need to be considered when planning a project? Choose three answers

Marina CMI [18]

Answer: Resolution or DPI, deliverables, and file types are important technical and visual demands to consider when planning a project.

Explanation: Keep in mind whether or not the project will be published in print or on the Web.

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3 years ago

Which principle of design does a designer apply when they create rhythmic movement in a garment by using recurring pleats or det

WITCHER [35]

Answer:

Repetition, and regular rhythm

Explanation:

Its certainly repetition method, and repetition method is of three types which are repetition, pattern and rhythm.

Remember repetition can be boring at times as we need to read same thing again and again. However, repetition sometimes can be good like the one we are referring to, and the other one can be like placing the logo or menu at same place in all web page. And its since it creates a habit in us for reading the web pages, And hence we can understand faster, and it looks please to our eyes hence as well.

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3 years ago

1. How many bits would you need to address a 2M × 32 memory if:

Dominik [7]

Answer:

a) 23 b) 21
a) 43 b) 42
a) 0 b) 0

Explanation:

1) How many bits is needed to address a 2M * 32 memory

2M = 2^1*2^20, while item =32 bit long word

hence ; L = 2^21 ; w = 32

a) when the memory is byte addressable

w = 8; L = ( 2M * 32 ) / 8 = 2M * 4

hence number of bits = log2(2M * 4)= log2 ( 2 * 2^20 * 2^2 ) = 23 bits

b) when the memory is word addressable

W = 32 ; L = ( 2M * 32 )/ 32 = 2M

hence the number of bits = log2 ( 2M ) = Log2 (2 * 2^20 ) = 21 bits

2) How many bits are required to address a 4M × 16 main memory

4M = 4^1*4^20 while item = 16 bit long word

hence L ( length ) = 4^21 ; w = 16

a) when the memory is byte addressable

w = 8 ; L = ( 4M * 16 ) / 8 = 4M * 2

hence number of bits = log 2 ( 4M * 2 ) = log 2 ( 4^1*4^20*2^1 ) ≈ 43 bits

b) when the memory is word addressable

w = 16 ; L = ( 4M * 16 ) / 16 = 4M

hence number of bits = log 2 ( 4M ) = log2 ( 4^1*4^20 ) ≈ 42 bits

3) How many bits are required to address a 1M * 8 main memory

1M = 1^1 * 1^20 , item = 8

L = 1^21 ; w = 8

a) when the memory is byte addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

hence number of bits = log 2 ( 1M ) = log2 ( 1^1 * 1^20 ) = 0 bit

b) when memory is word addressable

w = 8 ; L = ( 1 M * 8 ) / 8 = 1M

number of bits = 0

5 0

3 years ago

What is a form of technology that you think will make your life easier?

zzz [600]

Answer:

Digital communication technologies

Explanation:

connecting people across the globe has become easier and faster. Platforms such as Zoom, Room, Microsoft teams, WebEx, and many others are buzzing virtual world spaces to connect and share.

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3 years ago