A ball is thrown from an initial height of 2 meters with an initial upward velocity of 9/ms
Balls height 
To find all values of t for which the ball's height is 3 meters
We plug in 3 for h and solve for t
Solve for t
Solve using quadratic formula
After simplifying this,
= 0.11898
= 1.68102
the values of t for which the ball's height is 3 meters= 0.12 sec , 1.68 sec
1 bag per 5 minutes.
If you divide 15(total amount of min) by 3(bags of popcorn you popped) you will see you popped 1 bag per 5 minutes.
Now its say per minutes, then, you will have to say 1/5 bag per minutes.
Student P:
They messed up in step 1 because they made the 7.75 positive instead of negative, which causes the entire solution to be wrong
Student Q:
They were correct up until step 3. They didn't take all the negatives out of the equation (ex. -(3.5+7.75+29.67)).
Complete set:
From the picture, it looks like the original problem was
-2.5(1.4+3.1)+6.9(-4.3)
Step 1: multiply
1.4(-2.5)+3.1(-2.5)+6.9(-4.3)
Step 2: subtract (add?) them all together
-3.5-7.75-29.67
Step 3 should equal -40.92
Answer:
f(18)=334
Step-by-step explanation:
- f(x)=13x+100
- f(18) = 13(18)+100
- f(18)=234+100
- f(18)=334
Answer:
Step-by-step explanation:
The ratio of 6:30 would be equivalent to it.
