I hope this helps you
A=Area
b=base
h=height
A=b×h/2
A=1/2.b+1/2.h
Given:
Angle A = 18.6°
Angle B = 93°
Length of side AB = 646 meters
To find:
the distance across the river, distance between BC
Steps:
Since we know the measure of 2 angles of a triangle we can find the measure of the third angle.
18.6° + 93° + ∠C = 180°
111.6° + ∠C = 180°
∠C = 180° - 111.6°
∠C = 68.4°
Therefore the measure of angle C is 68.4°.
now we can use the law of Sines,


![BC[sin(68.4)] = 646 [sin(18.6)]](https://tex.z-dn.net/?f=BC%5Bsin%2868.4%29%5D%20%3D%20646%20%5Bsin%2818.6%29%5D)



meters
Therefore, the distance across the river is 222 meters.
Happy to help :)
If anyone need more help, feel free to ask
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The baker made 10 total muffins on monday
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Step-by-step explanation:
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Step-by-step explanation:
I don't say u must have to mark my ans as brainliest but if it has really helped u plz don't forget to thank me my frnd..
Answer:
7
Step-by-step explanation:
7x + 68 = 2x + 103
Subtract 2x from each side
5x + 68 = 103
Subtract 68 from each side
5x = 35
divide 5 from 35 and you get X = 7