Since y is .95 and x is 1 it is a unit rate which is the constant of proportionality.
Correct me if I am wrong.
Answer:
D Neither
Step-by-step explanation:
D neither
Hope it helps you in your learning process.
Answer:
x = 3
Step-by-step explanation:
We are told that the length of a side of the square is x.
Now, perimeter of square = 4 × side length
Perimeter of square = 4x
Also,we are told that the triangle is equilateral and a side is (x + 1).
Thus, perimeter of triangle = 3(x + 1)
Since we are told that the perimeter of the square is equal to that of the equilateral triangle. Thus;
4x = 3(x + 1)
4x = 3x + 3
Subtract 3x from both sides to get;
4x - 3x = 3
x = 3
y = 0.012x + 0.65<span><span><span>
Number of pages </span>
<span> 50.00 </span><span> 100.00 </span><span> 150.00 </span>
<span> 200.00 </span>
</span>
<span>
<span>
Cost </span>
<span> 1.25 </span>
<span> 1.85 </span>
<span> 2.45 </span>
<span> 3.05
x = number of pages
y = cost
intervals of x = 50 pages
intervals of y = 0.60
0.60 / 50 = 0.012
y = 0.012x + 0.65
</span></span></span><span>
<span>
</span><span><span>
<span> x </span>
<span> 0.012*x </span>
<span> y </span>
</span>
<span>
0.012
<span> 50 </span>
<span> 0.60 </span>
<span> 0.65 </span>
<span> 1.25
</span></span><span>0.012
<span> 100 </span>
<span> 1.20 </span>
<span> 0.65 </span>
<span> 1.85
</span>
</span>
<span>
0.012
<span> 150 </span>
<span> 1.80 </span>
<span> 0.65 </span>
<span> 2.45
</span>
</span>
<span>
0.012
<span> 200 </span>
<span> 2.40 </span>
<span> 0.65 </span>
<span> 3.05 </span>
</span></span></span><span>
</span>
Answer:
See possible solutions below.
Step-by-step explanation:
The statements are not given. But the following can be determined from the graph:
- More days recorded temperatures between 82 and 84 then other temperatures.
- The least number of days recorded temperatures between 88 and 90.
- The histogram is skewed to the right also known as positive skewed distribution.
- The mean and median will most likely be in the range of 82-84 temperatures. But the mean will be greater than the median.
