1.) The sum(addition) of 21 and 5 times(multiplication) a number f is(=) 61.
f = unknown number/variable [So 21 plus 5f(5 times f) equals 61]
21 + 5f = 61 [21(one-time) + 5f(number x variable) = 61(total)]
2.) Seventeen more(addition) than seven times(multiplication) a number j is(=) 87.
j = unknown number/variable [So 17 plus 7j(7 times j) equals 87]
17 + 7j = 87
3.) n = number of calls
18 + 0.05n = 50.50
[Company charges $18 plus five cents per call(n), and the total charge was $50.50]
4.) s = the number of students
40 + 30s = 220
[Tutor charges $40 plus $30 per student(s), and the total charge was $220]
Answer:
The Missing Length = 7
Step-by-step explanation:
Equation: side length x side length = area
- This means that if you divide the area by one of the side lengths, you'll find the other
1. Convert the numbers into decimals
- 8 3/4 - 8.75 (area)
- 1 1/4 = 1.25 (side length)
2. Divide the <u>area</u> by the <u>side length</u>
<u></u>
<u>7</u> is the answer.
Answer:
11.25
Step-by-step explanation:
Since AB and CD are parallel, ∠D is congruent to ∠A and ∠C is congruent to ∠B. Therefore the two triangles are similar by the AA postulate. Now, the corresponding sides are in proportion
Since AE ↔ DE and AB ↔ CD
So, AE/CD = AB/CD
AE/5 = 9/4
AE = 9(5)/4
= 45/4 = 11.25
Answer:
.
Step-by-step explanation:
Dilate a point 
by a scale factor of 
with 
as the center, and the resultant point would be at 
.
In this question:
Point to dilate: 
.
Scale factor: 
.
Center of dilation: 
.
The resultant point would be:
, which simplifies to .
Answer:
8 grams
Step-by-step explanation:
The balance is in equilibrium, so the weights of the two sides are equal.
Let the weight of a square be s.
Left side: 2s + 4
Right side: s + 3(4) = s + 12
The weights are equal, so we set the two expressions equal.
2s + 4 = s + 12
s = 8
Answer: The weight of a square is 8 grams.
