I'll say the first integer is x. The next consecutive odd number would be x+2. If the sum of the odd integers is 236, the equation would be
x + (x + 2) = 236
solve for x
2x + 2 = 236
subtract 2 from each side of the equation
2x = 234
divide both sides by 2
x = 117
117 is the first odd integer. to find the other integer (x + 2), substitute 117 for x, and you have 117 + 2, which equals 119
The two consecutive odd integers that add up to 236 are 117 and 119.
1/3 of 72 is 24 subtract 24 from 72 and get 48 and 1/4 of 48 is 12 so you subtract 12 from 48 and get 36 there for you have 36 dollars left over
5/x^2-1^2 + 3/x+1
5/(x+1)(x-1) + 3/x+1
5+3(x-1)/(x+1)(x-1)
5+3x-3/(x+1)(x-1)
Final answer : 3x+2/(x+1)(x-1)
Answer: n=3
Step-by-step explanation:
Divide by - 2
(N+3) = 6
Subtract 3
N= 3
Linear programming which shows the best investment strategy for the client is Max Z=0.12I +0.09B and subject to constraints are :I+ B<=25000,
0.005 I +0.004B<=250.
Given maximum investment client can make is $55000, annual return= 9%, The investment advisor requires that at most $25,000 of the client's funds should be invested in the internet fund. The internet fund, which is the more risky of the two investment alternatives, has a risk rating of 5 per thousand dollars invested. the blue chip fund has a risk rating of 4 per thousand dollars invested.
We have to make a linear programming problem.
Let
I= Internet fund investment in thousands.
B=Blue chip fund investment in thousands.
Objective function:
Max Z=0.12I+0.09B
subject to following constraints:
Investment amount: I+ B<=25000
Risk Rating: 5/100* I+4/100*B<=250 or 0.005 I +0.004B<=250
I,B>=0.
Hence the objective function is Max Z=0.12 I+ 0.09 B.
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