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2 years ago

What is 3/20 written as a percent?

Mathematics

2 answers:

Mariulka [41]2 years ago

8 0

Answer is provided in the image attached.

alex41 [277]2 years ago

6 0

Express it as a decimal.

3/20 = 0.15 by division

then move the decimal point twice to the right and affix the percent symbol

thus, 15%.

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If angle∠ A and angle∠ B are supplementary angles and angle∠ A is eighteight times as large as angle∠ B, find the measures of a

Shalnov [3]

A = 8B
A + B = 180
8B + B = 180
9B = 180
B = 20
A = 8 * 20 = 160

4 0

2 years ago

What is the measure of X?

AnnZ [28]

Answer:

A. 25.7°

Step-by-step explanation:

the sum of straight angle is 180°.

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i get 25.7 °

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2 years ago

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3 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

A.

The student made an error in step 3 because a is positive in Quadrant IV; therefore,

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

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Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

The student's mistake is that a is positive in quadrant iv and his error is in step 3

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2 years ago

Please HELP IM FALLING MATH PLEASE HELP

Ann [662]

Answer:

Step-by-step explanation:

32+35=67

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8 0

2 years ago