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3 years ago

Which is the simplified form of 7+5-12?

Mathematics

1 answer:

antiseptic1488 [7]3 years ago

4 0

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A young sumo wrestler decided to go on a diet to gain weight rapidly. He gained weight at a rate of 5.5kg a month. After 11 mont

kondaur [170]

Answer:

$W(t)=5.5t+79.5$ .

Step-by-step explanation:

Please consider the complete question.

A young sumo wrestler decided to go on a special high-protein diet to gain weight rapidly. He gained weight at a rate of 5.5 kilograms per month. After 11 months, he weighed 140 kilograms. Let W(t) denote the sumo wrestler's weight W(measured in kilograms) as a function of time t (measured in months).

Since wrestler gained weight at a rate of 5.5 kilograms per month, so slope of line be 5.5.

Now, we will use point-slope form of equation as:

$y-y_1=m(x-x_1)$ , where,

m = Slope

$(x_1,y_1)$ = Given point on the line.

Upon substituting coordinates of point (11,140) in above formula, we will get:

$y-140=5.5(x-11)$

$y-140=5.5x-60.5$

$y-140+140=5.5x-60.5+140$

$y=5.5x+79.5$

Therefore, our required function would be $W(t)=5.5t+79.5$ .

3 0

3 years ago

What is the equation for the graph below?

Eddi Din [679]

Use Desmos graphing calculator and plug in the different equations.

3 0

3 years ago

What is the product ?

Olenka [21]

Answer:

The answer to your question is:

Step-by-step explanation:

$\frac{x^{2}-16 }{2x + 4} \frac{x^{3}-2x^{2} + x }{x^{2}+ 3x - 4}$

Factorize $\frac{(x+4)(x-4)}{2(x+2)} \frac{x(x^{2}-2x + 1) }{(x+4)(x-1)}$

Factorize $\frac{(x+4)(x-4)}{2(x+2)} \frac{x(x-1)^{2} }{(x+4)(x-1)}$

Simplify $\frac{x(x-4)}{2(x+2)}$

7 0

3 years ago

What is the area of this square?

shepuryov [24]

Area = 40x40 = 1600<span>km²

answer

</span><span>D.
1,600 km²</span>

5 0

3 years ago

Read 2 more answers

if you see this I really need help on this question asap ty so much... "The flagpole in the diagram below has a height of 10ft.

aev [14]

Answer:

15.62 feet

Step-by-step explanation:

If the flagpole is 10ft tall and the shadow is 12ft long, and you need to find the distance from the top of the flagpole to the far end of the shadow, to get your answer, you must use the pythagorean theorum.

$a^{2} + b^{2} = c^{2}$

let height of flagpole = a

let length of shadow = b

let distance between the two = c

$10^{2} + 12^{2} = c^{2} \\100 + 144 = c^{2}\\244 = c^{2}\\\sqrt{244} = \sqrt{c^{2}} \\\sqrt{244} = c\\15.62 = c$

7 0

3 years ago