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Nata [24]
3 years ago
12

Sovle for x in the equation x2+14+17 =-96

Mathematics
2 answers:
Ket [755]3 years ago
8 0

Solve for x in the equation x2+14x+17=-96.

x=-7+_4/6i

x = –7 ± 8i

x+7+_4/6i

x = 7 ± 8i

MrMuchimi3 years ago
4 0
Hello!

You solve this algebraically

x^{2} + 14 + 17 = -96

Combine like terms

x^{2} +31 = -96

Subtract 31 from both sides

x^{2} =-127

Take the square root of both sides

x = \sqrt{127} i

Hope this helps!

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Find KL in the image below.
gtnhenbr [62]

Answer:

k\:is \: the \: mid \: opint \: of \:GF

L\:is\:the \:mid\:point\:of GH

KL=1/2(16)

KL=8

<u>OAmalOHopeO</u>

7 0
3 years ago
What is Permutations and Combinations?
marissa [1.9K]

Answer:

See below

Step-by-step explanation:

Permutation is to select an object then arrange it and it cares about the orders while Combination is about only selecting an object without caring the orders.

Permutation can be expressed in math as:

\displaystyle{_n P _r = \dfrac{n!}{(n-r)!} \ \ \ (n \geq r) }

where n is a number of total object and r is a number of selected object to arrange. Hence. n cannot be less than r.

Now let's see an example of permutation, suppose we have letter A, B and C. I'd like to know how many ways these words can be arranged:

Since there are 3 letters total and 3 selected letters to arrange then:

\displaystyle{_3 P _3 = \dfrac{3!}{(3-3)!}}\\\\\displaystyle{_3 P _3 = \dfrac{3 \times 2 \times 1}{0!}}\\\\\displaystyle{_3 P _3 = \dfrac{6}{1}}\\\\\displaystyle{_3 P _3 = 6}

Therefore, there are 6 ways to arrange the letters - we can also demonstrate visually:

ABC - 1

ACB - 2

BAC - 3

BCA - 4

CAB - 5

CBA - 6

Notice that if you do visually, you'll get the same answer as the calculation of permutation!

----

Combination can be expressed mathematically as:

\displaystyle{_n C _r = \dfrac{n!}{(n-r)!r!} = \dfrac{_n P _r}{r!} \ \ \ (n \geq r) }

The difference between permutation and combination is that you only find how many ways you can select object in combination. Therefore, no arrange and doesn't care about order, just ways to select.

Suppose we have same 3 letters: A, B and C. I want to find how many ways I can select these 3 letters:

Since there are 3 letters total and 3 selected letters:

\displaystyle{_3 C _3 = \dfrac{3!}{(3-3)!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{0!3!}}\\\\\displaystyle{_3 C _3 = \dfrac{3!}{3!}}\\\\\displaystyle{_3 C _3 = 1}

Hence, there is only one way to select 3 letters. This makes sense because if you have 3 letters then you can only select 3 letters only one way.

5 0
2 years ago
2. Carol wants to find how many people in her town own a dog as a pet. She decides to survey
kaheart [24]
This is not a random sample since she is outside of a pet store and the probability of people owning a dog coming out of that store is very very high. If she went around the neighborhood and knocked on people’s door and asked if they had a dog or not would be random sample.
6 0
3 years ago
Jsjjss pls help its uRGeNT
Sedaia [141]

Answer: y=7x

Step-by-step explanation:

The way I did it was, I looked at the chart. The highest it goes is 30 and 210. So for your answer, you have to multiply. 7x30 gives you 210 and there y=7x

5 0
3 years ago
If guy walks from his house to school and back,how far does he walk?
Serga [27]
He walked the same distance to school and back home.
I hope this helped! :-)
8 0
3 years ago
Read 2 more answers
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