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RideAnS [48]
3 years ago
10

Write a paragraph comparing the two classes' semester grades. Be sure to compare the extremes, the quartiles, the medians, and t

he different types of ranges. Give as much information as possible.

Mathematics
1 answer:
Gnom [1K]3 years ago
3 0

Answer:

Second class have higher marks and greater spread.

Step-by-step explanation:

First box plot  represents class first. From the first box plot, we get

\text{Minimum value }= 53,Q_1=62,Median=80,Q_3=86,\text{Maximum value }= 89

Range=Maximum-Minimum=89-53=36

IQR=Q_3-Q-1=86-62=24

Second box plot  represents class second. From the second box plot, we get

\text{Minimum value }= 56,Q_1=62,Median=74,Q_3=89,\text{Maximum value }= 96

Range=Maximum-Minimum=96-56=40

IQR=Q_3-Q-1=89-62=27

First class has greater minimum value, first quartile of both classes are same, second class has greater median, first class has greater third quartile and first class has greater maximum value. It means second class have higher marks but class first have less variation.

Second class has greater range and greater inter quartile range. It means data of second class has greater spread.

Therefore, second class have higher marks and greater spread.

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Stephen is testing the difference in means between time it takes to travel school in a bus and time it takes to travel to school
EastWind [94]

Answer:

Kindly check explanation

Step-by-step explanation:

To test for Difference in mean times

Null hypothesis, H0 will be, there is no difference in mean times ; m1 = m2

Alternative hypothesis, there is difference in mean times ; m1 ≠ m2

Decision region :

When p value < α ; reject the Null

Here. ;

Pvalue = 2% = 0.02

α = 1% = 0.01

Pvalue > α

0.02 > 0.01

Since, Pvalue > α ; we do not reject the Null ;

Hence, conclusion should be, there is no difference in mean times of bus and car

8 0
3 years ago
If 2x = 20, then x is <br> a. 5. b. 10. c. 20.
Sergeeva-Olga [200]

Answer:

B. 10

Step-by-step explanation:

To find the answer we would plug each given number into x to see if it makes the equation true

<em>A. 2(5) = 20 </em>

<em>     10 </em>\neq<em> 20</em>

<em>B. 2(10) = 20</em>

<em>     20 = 20</em>

<em>C. 2(20) = 20</em>

<em>     40 </em>\neq<em>20</em>

As you can see, the only answer that makes the equation 2x=20 true, is answer B

7 0
3 years ago
Read 2 more answers
Based on the information on the diagram, what is the measure of angle ADC?​
Serga [27]

Answer:

73°

Step-by-step explanation:

Given: BD=BE

           ∠DBE= 50°

            ∠EAC= 42°

           DE//AC and AE=CD

Attach is the new drawn diagram with M point.

∵ we know BD=BE, ∴ ∠BDE=∠BED= x ( taking x as unknown angle)

Remember, sum of triangle= 180°

Now, ∠BDE+∠BDE+∠DBE= 180°

⇒  x+x+50= 180

⇒ 2x+50= 180

Subtracting both side by 50, then dividing both side by 2

∴ x= \frac{130}{2}= 65°

We know, ∠MAC= ∠MCA= 42° (∵AM=MC)

Next, ∠EDC=DCA= 42° ( ∵ Alternate interior angle as we know DE//AC )

Now, we have ∠EDC= 42°, ∠BDE= 65°

∴ BDE+EDC+ADC= 180° (∵sum of straight line= 180°)

⇒ 65+42+ADC= 180°

⇒107+ADC= 180°

Subtracting both side by 107

∴∠ADC= 180-107= 73°

∴∠ADC= 73°

7 0
3 years ago
Three of the angles of a quadrilateral are 53°, 127° and 72°. What is the size of the 4th angle?
EleoNora [17]
The size of the fourth angel = 360 - ( 53 + 127 + 72 ) = 108
4 0
4 years ago
F(t) = -(t-2) (t-15)
Goryan [66]

Answer:

smaller (t) = 2 and this in coordinates form (2,0)

larger (t) = 15 and this in coordinates form (15,0)

the vertex of the parabola =  (\frac{17}{2} ,\frac{169}{4} ) or in decimals (8.5, 42.25)

Step-by-step explanation:

  • For the zeros of the function take each bracket and make it equal to zero.

SMALLER (t):

(t-2)=0

(add 2 for both sides)

t=2

LARGER (t):

(t-15)=0

(add 15 for both sides)

t=15

  • For the vertex of the parabola you do:

step1: expand the brackets:

f(t)=-(t-2)(t-15)

f(t)= -t^{2} +17t-30

step2: define a,b and c using the expression ax^{2} +bx+c :

a= -1 (the coefficient of t^{2} )

b= 17 (the coefficient of t)

c= -30 (the single number without a letter)

step3: sub the values in the formula -\frac{b}{2a} to find the x coordinate of the vertex :

-\frac{b}{2a}

= - \frac{17}{2*-1}

= \frac{17}{2} or in decimals 8.5

step4: sub the value of t (the x-coordinate) in equation f(t):

f(t)= -t^{2} +17t-30

f ( \frac{17}{2})  = - (\frac{17}{2} )^{2}+ 17× \frac{17}{2} - 30

= -\frac{289}{4} + \frac{289}{2} -30

=\frac{169}{4} or in decimals 42.25

(THIS IS A PICTURE OF THE GRAPH↓)

6 0
3 years ago
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