Answer:
E
Step-by-step explanation:
Hopefully this isn't too late. My work is attached below.
What's the vertex for 6x^2-48x-54=0?
1 answer:
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The approximate solution of the above equation is: 55/15 (Option A). This is solved using the quartic formula, not quadratic equation.
<h3>What is the Quartic Formula?</h3>
The quartic formula has up to four various solutions including real and imaginary numbers. Read on for more explanation.
<h3>What is the solution to the above question?</h3>
First we restate the above equation:
x²-3x+2= √(x-2) + 2
Next we remove square roots - 6x³ + 9x² = x - 2
Add two to both sides
→ - 6x³ + 9x²+2 = x - 2 +2
→ - 6x³ + 9x²+2 = x
Subtract X from both sides
→ - 6x³ + 9x²+2 -x = x -x
→ - 6x³ + 9x²+2 - x= 0
Using the Quartic formula to solve the fourth order equation:
a + bx³ + cx² + dx + e
The resolution of x is given as:
x = 2.691085, 3.346753
Because the fraction nearest to 3.4 is 55/16
hence, the correct answer is Option A.
Learn more about quadratic equations at;
brainly.com/question/25841119
#SPJ1
Given:
The expression is .
To find:
The position of parentheses inserted in the expression to get the value 19
Step-by-step explanation:
We have,
Now,
There are more ways to apply the parenthesis, but we do not get 19.
And many more possibilities.
Therefore, the expression after inserting the parentheses is .
Answer:
See explanation
Step-by-step explanation:
In ΔABC, m∠B = m∠C.
BH is angle B bisector, then by definition of angle bisector
∠CBH ≅ ∠HBK
m∠CBH = m∠HBK = 1/2m∠B
CK is angle C bisector, then by definition of angle bisector
∠BCK ≅ ∠KCH
m∠BCK = m∠KCH = 1/2m∠C
Since m∠B = m∠C, then
m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)
Consider triangles CBH and BCK. In these triangles,
- ∠CBH ≅ ∠BCK (from equality (*));
- ∠HCB ≅ ∠KBC, because m∠B = m∠C;
- BC ≅CB by reflexive property.
So, triangles CBH and BCK are congruent by ASA postulate.
Congruent triangles have congruent corresponding sides, hence
BH ≅ CK.
