What's the vertex for 6x^2-48x-54=0?

Mathematics

1 answer:

kakasveta [241]3 years ago

4 0

It would be 4,-25 becuase of in the first place i in and the other imp in cams was the

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Elisa needs 40 shirts for a charity. One store is selling shirts for $6.95 each. Another store says that the total for al 40 shi

xxTIMURxx [149]

Well, let us figure out what the first store will cost.
40*6.95=278
Now for the second store
325*0.8=260

So the first store is $278, while the second store is $260, so Elisa should buy shirts from the second store

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3 years ago

Find the future value of the annuity due for $200 deposited at the beginning of each quarter for 12 years at 7% compounded quart

dimulka [17.4K]

200*(107%)^x

x is the number of quarters that passed.
each year has 4 quarters, so 12 yaers would have: 12*4 = 48 quarters

200*(107%)^48 = 5146

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3 years ago

The product of two numbers is 21. If the first number is -3 which equation respents this situation and what is the second number

Vaselesa [24]

Let the second no. be x

-3x = 21 → x = 21/-3 → x = -7

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1 year ago

Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

Vikentia [17]

Answer:

Step-by-step explanation:

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4 years ago

A mass weighing 3 lb stretches a spring 3 in. If the mass is pushed upward, contracting the spring a distance of 1 in and then s

Bas_tet [7]

Answer:

Step-by-step explanation:

$m=\frac{3}{32}\\ \gamma =0\text{ damping constant.}\\ k=\frac{3}{\frac{1}{4}}=12\\ F(t)=0\\ \text{so equation of motion is }\\ mu''+\gamma u'+ku=F(t)\\ \frac{3u''}{32}+12u=0\\ u''+128u=0\\ \text{and initial conditions are}\\ u(0)=-\frac{1}{12}\\ u'(0)=2\\ u''+128u=0\\ \text{characterstic equation is}\\ r^2+128=0\\ \text{roots are }\\ r=\pm 8\sqrt{2}i\\ \text{therefore general solution is}\\ u(t)=A\cos8\sqrt{2}t+Bsin8\sqrt{2}t\\ \text{using initial conditions we get}\\ A=-\frac{1}{12}\\ B=\frac{\sqrt{2}}{8}\\ \text{therefore solution is }\\ u(t)=-\frac{1}{12}\cos8\sqrt{2}t+\frac{\sqrt{2}}{8}\sin8\sqrt{2}t\\
{hence}\\R=\sqrt{\frac{11}{288}}\\\\\sigma=\pi - \tan^{-1}\frac{1}{\sqrt{2}}\\\\\omega_0=8\sqrt{2}\\T=\frac{4}{4\sqrt{2}}$

3 0

3 years ago