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8090 [49]
3 years ago
13

An egg rolls off a kitchen counter and breaks as it hits the floor. The counter is 1.0 m high, the mass of the egg is about 50 g

, and the time interval during the collision is about 0.010 s.
How large is the impulse that the floor exerts on the egg?
use equations of motion to find the velocity just before it hits the floor:
Vf^2 = Vi^2 + 2gx Final velocity = 4.42m/s Impulse is change in momentum so: m(Vf - Vi) = 0.05(0 - 4.42) = - 0.221 kg.m/s
Physics
1 answer:
crimeas [40]3 years ago
3 0
Use equations of motion to find the velocity just before it hits the floor: 
<span>Vf^2 = Vi^2 + 2gx </span>
<span>Final velocity = 4.42m/s </span>

<span>Impulse is change in momentum so: </span>
<span>m(Vf - Vi) = 0.05(0 - 4.42) </span>
<span>= - 0.221 kg.m/s

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions here.

</span>
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If a steady-state heat transfer rate of 3 kW is conducted through a section of insulating material 1.0 m2 in cross section and 2
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Answer:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

So then the difference of temperature across the material would be \Delta T = 375 K

Explanation:

For this case we can use the Fourier Law of heat conduction given by the following equation:

Q = -kA \frac{\Delta T}{\Delta x}   (1)

Where k = thermal conductivity = 0.2 W/ mK

A= 1m^2 represent the cross sectional area

Q= 3KW represent the rate of heat transfer

\Delta T is the temperature of difference that we want to find

\Delta x=2.5 cm =0.025 m represent the thickness of the material

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\Delta T =\frac{Q \Delta x}{Ak}

First we convert 3KW to W and we got:

Q= 3 KW* \frac{1000W}{1 Kw}= 3000 W

And we have everything to replace and we got:

\Delta T = \frac{3000 W *0.025 m}{1 m^2 (0.2 \frac{W}{mK})}= 375 K

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