Answer:
![\displaystyle \Delta x=1.74\ m](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5CDelta%20x%3D1.74%5C%20m)
Explanation:
<u>Elastic Potential Energy
</u>
Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.
![\displaystyle PE = \frac{1}{2}k(\Delta x)^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20PE%20%3D%20%5Cfrac%7B1%7D%7B2%7Dk%28%5CDelta%20x%29%5E2)
Given a rubber band of a spring constant of k=5700 N/m that is holding potential energy of PE=8600 J, it's required to find the change of length under these conditions.
Solving for Δx:
![\displaystyle \Delta x=\swrt{\frac{2PE}{k}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5CDelta%20x%3D%5Cswrt%7B%5Cfrac%7B2PE%7D%7Bk%7D%7D)
Substituting:
![\displaystyle \Delta x=\sqrt{\frac{2*8600}{5700}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5CDelta%20x%3D%5Csqrt%7B%5Cfrac%7B2%2A8600%7D%7B5700%7D%7D)
Calculating:
![\displaystyle \Delta x=\sqrt{3.0175}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5CDelta%20x%3D%5Csqrt%7B3.0175%7D)
![\boxed{\displaystyle \Delta x=1.74\ m}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdisplaystyle%20%5CDelta%20x%3D1.74%5C%20m%7D)
The ammonium salt of acetic acid is the reaction product of acetic acid and ethylamine at room temperature
<h3 /><h3>What is acetic acid ?</h3>
Acetic acid is a monofunctional carboxylic acid containing two carbon atoms. It acts as a protein solvent, food acidity regulator, antibacterial food preservative. It is a conjugate acid of an acetate.
Acetic acid is used in the production of acetic anhydride, cellulose acetate, vinyl acetate monomer, acetic ester, chloroacetic acid, plastics, dyes, insecticides, photographic chemicals, and rubber. Other commercial uses include the production of vitamins, antibiotics, hormones, organic chemicals, and as a food additive. Typical concentrations of acetic acid found naturally in foods are 700 to 1200 milligrams/kg (mg/kg) in wine, up to 860 mg/kg in aged cheeses, and 2.8 mg/kg in aged cheeses. fresh orange juice.
learn more about acetic acid, visit;
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Write out what you have which is:
initial velocity
final velocity
Y distance
degree
You do not have :
a
X distance
t
from what you have you can plug into your formulas to get time.
Answer:
Speed of another player, v₂ = 1.47 m/s
Explanation:
It is given that,
Mass of football player, m₁ = 88 kg
Speed of player, v₁ = 2 m/s
Mass of player of opposing team, m₂ = 120 kg
The players stick together and are at rest after the collision. It shows an example of inelastic collision. Using the conservation of linear momentum as :
![m_1v_1+m_2v_2=(m_1+m_2)V](https://tex.z-dn.net/?f=m_1v_1%2Bm_2v_2%3D%28m_1%2Bm_2%29V)
V is the final velocity after collision. Here, V = 0 as both players comes to rest after collision.
![v_2=-\dfrac{m_1v_1}{m_2}](https://tex.z-dn.net/?f=v_2%3D-%5Cdfrac%7Bm_1v_1%7D%7Bm_2%7D)
![v_2=-\dfrac{88\ kg\times 2\ m/s}{120\ kg}](https://tex.z-dn.net/?f=v_2%3D-%5Cdfrac%7B88%5C%20kg%5Ctimes%202%5C%20m%2Fs%7D%7B120%5C%20kg%7D)
![v_2=-1.47\ m/s](https://tex.z-dn.net/?f=v_2%3D-1.47%5C%20m%2Fs)
So, the speed of another player is 1.47 m/s. Hence, this is the required solution.