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3 years ago

1. Which of the following best describes a nebula?

Physics

1 answer:

Gekata [30.6K]3 years ago

8 0

Answer:

Explanation:

denser clouds of particles found in the interstellar medium

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A book that weighs 20 N sits on a table. How big and in what direction does the force of gravity from the Earth act on the book?

taurus [48]

Answer:

A. 20 N down

Explanation:

It's asking how much force of gravity is acting on it. The book weighs 20 Newtons so that's how much gravity is being applied. Hope this helps

7 0

3 years ago

Read 2 more answers

8. Ella wants to replace old bulbs of her home with new LED bulbs. She buys LED bulb that has inbuilt AC to DC converter of outp

tankabanditka [31]

The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

<h3>What is electrical power?</h3>

Electrical power is the rate at which electrical work is done.

Electrical power = voltage × current

The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.

Total power dissipated = 5 × 2.5 = 12.5 Watts

Work done = power × time (in seconds)

Work done = 12.5 × (1 × 3600 + 15 × 60)

Work done = 56250 J = 56.25 kJ

Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.

Learn more about electrical power and work done at: brainly.com/question/23901751

#SP1

3 0

2 years ago

PLEASE HELP I HAVE FINALSSS

vitfil [10]

Answer: 26.67 m/s

Explanation:

Given

Length traveled by the ball $s=40\ m$

Time taken to reach the goal post is $t=3\ s$

Initial velocity $u=0\ m/s$

Using the second equation of motion

$\Rightarrow s=ut+\frac{1}{2}at^2\\\Rightarrow 40=0+\frac{1}{2}a(3)^2\\\Rightarrow a=\frac{80}{9}\ m/s^2\\$

Now using

$\Rightarrow v^2-u^2=2as\\\\\Rightarrow v^2-0=2\times \frac{80}{9}\times 40\\\\\Rightarrow v=\sqrt{\dfrac{80\times 80}{9}}=\dfrac{80}{3}\\\Rightarrow v=26.67\ m/s$

The velocity of ball will be 26.67 m/s

8 0

3 years ago

213.49 in standard form is

Rudiy27

Answer:

21349/ 100

Explanation:

7 0

3 years ago

(1) Develop an equation that relates the rms voltage of a sine wave to its peak-to-peak voltage. a. If a sine wave has a peak-to

Aleks04 [339]

Answer:

(A) Equation will be $v=v_msin\omega t=0.75sin(18840t)$

(B) RMS value of voltage will be 0.530 volt

Explanation:

We have given peak to peak voltage of ac wave = 1.5 volt

Peak to peak voltage of ac wave is equal to 2 times of peak voltage

So $2v_{peak}=1.5volt$

$v_{peak}=\frac{1.5}{2}=0.75volt$

Frequency of ac wave is given f = 3 kHz

So angular frequency $\omega =2\pi f$ = 2×3.14×3000 = 18840 rad/sec

So expression of equation will be $v=v_msin\omega t=0.75sin(18840t)$ ( As phase difference is 0 )

Now we have to find the rms value of voltage

So rms voltage will be equal to $v_{rms}=\frac{v_{peak}}{\sqrt{2}}=\frac{0.75}{1.414}=0.530volt$

4 0

3 years ago