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3 years ago

Is The polar form of a complex number is unique?

Mathematics

1 answer:

Pie3 years ago

6 0

Answer:

Step-by-step explanation:

The angle in the polar form of a complex number can have any multiple of 2π radians added to it, and the number will be the same number. That is, there are an infinite number of representations of a complex number in polar form.

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Solve the linear system of equations using the linear combination method.<br> 4x-9y=20<br> 2x-6y=16

maxonik [38]

The solution is (-4,4)

Step-by-step explanation:

Given equations are:

$4x-9y = 20\ \ \ \ Eqn1\\2x-6x = 16\ \ \ \ Eqn2$

In linear combination method, we have to make coefficients of any one variable opposites by multiplying with an integer

So multiplying 2nd equation by -2

$-2(2x-6y=16)\\-4x+6y=-32\ \ \ \ Eqn3$

Adding Equation 1 and Equation 3:

$4x-9y-4x+12y = 20-32\\3y = -12$

Dividing both sides by 3

$\frac{3y}{3} = \frac{-12}{3}\\y = -4$

Putting y=-4 in equation 1

$4x-9(-4) = 20\\4x +36= 20\\4x = 20-36\\4x = -16$

Dividing both sides by 4

$\frac{4x}{4} = \frac{-16}{4}\\x = -4$

Hence,

The solution is (-4,4)

Keywords: Linear combination, linear equations

Learn more about linear combination method at:

#LearnwithBrainly

3 0

3 years ago

What is the radius for a circle whose equation is x² + y² = 16?

tekilochka [14]

Answer:The radius is √16.

Step-by-step explanation:

7 0

1 year ago

Simplify the expression-3÷(-2/5)

BARSIC [14]

Answer:

15/2 or 7.5

Step-by-step explanation:

-3÷ (-2/5)

The reciprocal of -2/5 is -5/2

So we multiply -3 into the reciprocal of the fraction and we can get the same answer

Therefore,

-3÷(-2/5)

= -3x -5/2

= (-5x-3)/2

(Two negatives become a positive)

= 15/2 in fraction form

And 7.5 in decimal form

3 0

3 years ago

Read 2 more answers

In the given figure ABCD is a parallelogram, E is the midpoint of BC. DE produced meets AB produced at L. Prove that AB = B L an

aliina [53]

Answer:

<em>See Reasoning Below</em>

Step-by-step explanation:

To prove that AB = BL, or in other words AB ≅ BL, let us consider the triangles CED and BEL. If we were to prove they were congruent, then by CPCTC ( corresponding parts of congruent triangle are congruent ) DC ≅ BL. As AB ≅ DC by " Properties of Parallelogram " it would be that through transitivity, AB ≅ BL / AB = BL;

$m$

Now for " part 2 " we can consider that AB = DC, from part 1. If AB = BL, then AL = 2 ( AB ) by the Partition Postulate. AB = DC, so we can also say that AL = 2 ( DC ) - Proved

See attachment in statement reasoning form for part 1;