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ser-zykov [4K]
3 years ago
10

Is The polar form of a complex number is unique?

Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

  no

Step-by-step explanation:

The angle in the polar form of a complex number can have any multiple of 2π radians added to it, and the number will be the same number. That is, there are an infinite number of representations of a complex number in polar form.

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Solve this system
madam [21]

Answer:

Its the first option

Step-by-step explanation:

4 0
3 years ago
Please help with this question!
Naddika [18.5K]
I am pretty sure the answer is 14
6 0
3 years ago
Identify two additional values for x and y in a direct variation relationship where y =11 when x=18
Ann [662]
In a direct variation relationship the values must satisfy that y = kx. This si y is always a constant value (k) times x.

So, you can find multiple values that meet this:

y = kx => k = y / x = 11 / 18

=> y = (11/18)x

Now you can give any value to x and fint the value of x that satisfy the relationship:

x           y = (11/18)x

1           11/18

2           11/18 * 2 = 11/9

18          11/18 * 18 = 11

36           11/18 * 36 = 22

So, there you have several additional values for x and y in the same relationship that y = 11 and x = 18, and you can find many more using the same rule: y = (11/18)*x
3 0
3 years ago
PLEASE HELP QUICKLY!!!! What is the equation of the line with a slope of -3/4 that goes through the point (−6, 3)?
Yakvenalex [24]

Answer:

y=-\frac{3}{4}x-\frac{3}{2}

or

y=-0.75x-1.5

Step-by-step explanation:

step 1

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=-\frac{3}{4} \\point\ (-6,3)

substitute

y-3=-\frac{3}{4}(x+6)

step 2

Convert to slope intercept form

y=mx+b

we have

y-3=-\frac{3}{4}(x+6)

Isolate the variable y

y-3=-\frac{3}{4}x-\frac{9}{2}

y=-\frac{3}{4}x-\frac{9}{2}+3

y=-\frac{3}{4}x-\frac{3}{2}

4 0
3 years ago
Which of the following equations is on the same path as x=2-3t, y=7-6t?
Svet_ta [14]

Answer:

C. y = 3+2\cdot x

Step-by-step explanation:

Let be the parametric equations x = 2-3\cdot t and y = 7 - 6\cdot t, we need to clear t and eliminate it afterwards to obtain a function of the form y = f(x):

x = 2 - 3\cdot t

3\cdot t = 2 - x

t = \frac{2}{3}-\frac{1}{3}\cdot x (1)

y = 7 - 6\cdot t

6\cdot t = 7 - y

t = \frac{7}{6} - \frac{1}{6}\cdot y (2)

By (1) and (2):

\frac{2}{3}-\frac{1}{3}\cdot x = \frac{7}{6}-\frac{1}{6}\cdot y

4 -2\cdot x = 7 - y

y = 3+2\cdot x

Hence, the correct answer is C.

6 0
3 years ago
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