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3 years ago

8

Help me. I need help on multiply decimal with exponents

1 answer:

AleksAgata [21]3 years ago

3 0

Answer:

Step-by-step explanation:

for the first 2 questions 3.04 x 10^2 you would move the decimal over 2 places and 0.304 x 10^4 just move the decimal over4 places and you have your answer

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1.work out 1/2 + 5/6

Serggg [28]

1. First find the LCD of the two fractions.
They share the denominator 6.
Turn 1/2 into a fraction with a denominator of 6.
2*3=6, so 1*3=3
3/6
Now add.
Leave denominators alone, but add numerators.
3+5=8
8/6
Now simplify.
Divide both by 2.
8/2=4
6/2=3
4/3 is your answer or 1 1/3
2. Multiply straight across.
3*2=6
4*7=28
6/28
Simplify
You get 3/14 as your answer.

3 0

3 years ago

If cos 0 =8/17, what is sin 0?

ipn [44]

Answer:

sin=15/17

Step-by-step explanation:

Use the definition of sine to find the value of

sin (0)

sin (0) = opp/hyp

THEN

Substitute in the known values.

sin (0) = 15/17

3 0

1 year ago

Please help I’ll mark you as brainliest if correct

Len [333]

Answer:

I think it is option B

Step-by-step explanation:

I dont know if I am right

if I am your welcome

4 0

3 years ago

Read 2 more answers

A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet

Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

$L_{1} = 2W_{1}$

Also, the area of the walkway of 2 feet wide is 448:

$W_{2} = 2 ft$

$A_{T} = W_{2}*L_{2} = 448 ft^{2}$

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

$A_{T} = A_{1} + A_{w}$ (1)

The area of the pool is given by:

$A_{1} = L_{1}*W_{1}$

$A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}$ (2)

And the area of the walkway is:

$A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}$ (3)

Where the length of the bigger rectangle is related to the lower rectangle as follows:

$L_{2} = 4 + L_{1} = 4 + 2W_{1}$ (4)

By entering equations (4), (3), and (2) into equation (1) we have:

$A_{T} = A_{1} + A_{w}$

$A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}$

$448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}$

$224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}$

$224 = W_{1}^{2} + 8 + 6W_{1}$

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

$L_{1} = 2W_{1} = 2*12 ft = 24 ft$

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!

8 0

3 years ago

Guys plz help me answer this!!!!

Zolol [24]

Answer:

p= 2

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

6 0

3 years ago