Answer:
Step-by-step explanation:
<u>The full question:</u>
<em>"A committee has eleven members. there are 3 members that currently serve as the boards chairman, ranking members, and treasurer. each member is equally likely to serve in any of the positions. Three members are randomly selected and assigned to be the new chairman, ranking member, and treasurer. What is the probability of randomly selecting the three members who currently hold the positions of chairman, ranking member, and treasurer and reassigning them to their current positions?"</em>
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The permutation of choosing 3 members from a group of 11 would be:
P(n,r) = 
Where n would be the total [in this case n is 11] & r would be 3
Which is:
P(11,3) = 
So there are total of 990 possible way and there is ONLY ONE WAY for them to be reassigned. Hence the probability would be:
1/990
Cuando has simplificado la ecuación lo mas posible y las expresiones de los dos lados quedan iguales, hay soluciones infinitas. Pero, dado que lo has simplificado y son diferentes, no hay solución.
1.) 7x = 12 + 7x - 12
=> 7x = 7x => infinita solución
2.) x - 11 = 11 + x
=> x = 22 + x => no solución
3.) 2(4x - 6) = 8(x + 2)
=> 8x - 12 = 8x + 16 => 8x = 8x + 28 => no solución
4.) 2x - 9 = 2x - 9
=> infinita solución
5.) 8 + 4x = 4x + 10
=> 4x = 4x - 2 => no solución
Answer:
yes
Step-by-step explanation:
7 1/5:
Multiply the denominator and the whole number: 7*5 = 35 and then add the numerator: 35+1= 36/5. Then, do this for the following fraction, the improper fraction value of 2 2/15 is 32/15.
Now we need 36/5 & 32/15 to have common denominators so that we can simplify it a little less complicated.
For Instance,
36/5*3= 108/15
Now we divide, (108/15)/(32/15)
108/32= 3.375 = 3 3/8
Answer is 3 3/8.
Hope this was easy to understand!
Answer:
you need 100ml of 5X TAE and 400ml of water.
Step-by-step explanation:
You need to use a rule of three:
where:
and
Therefore:
Then just rest the TAE volume to the final Volume and you get the amount of water that you need to reduce the concentration.
