3 years ago

Radicals and Exponets

Mathematics

1 answer:

Yuliya22 [10]3 years ago

3 0

Answer:

nooo

Step-by-step explanation:

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4 years ago

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(csc x - 1) (csc x + 1)

victus00 [196]

<h2>Explanation:</h2>

Here we have the following expression:

$(csc x - 1) (csc x + 1)$

So we need to extend this. Remember that the difference of squares tells us:

$(a-b)(a+b)=a^2-b^2$

So here:

$a=cscx \\ \\ b=1$

Thus:

$(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}$

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3 years ago

For a science project, 3/4 of the students chose to make a poster and 0.25 of the students wrote a report. Rosa said that more s

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She’s right because .25 converted into a fraction is 1/4 and 3/4 is greater than 1/4

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