Answer:
<h2>
-27/4</h2>
Step-by-step explanation:
Given the quadratic polynomial given as g(x) = x²- 5x + 4, the zeros of the quadratic polynomial occurs at g(x) = 0 such that x²- 5x + 4 = 0.
Factorizing the resulting equation to get the roots
x²- 5x + 4 = 0
(x²- x)-(4 x + 4) = 0
x(x-1)-4(x-1) = 0
(x-1)(x-4) = 0
x-1 = 0 and x-4 = 0
x = 1 and x = 4
Since a and b are known to be the root then we can say a = 1 and b =4
Substituting the given values into the equation 1/a+1/b-2 ab
, we will have;
= 1/1 + 1/4 - 2*1*4
= 1 + 1/4 - 8
= 5/4 - 8
Find the Lowest common multiple
= (5-32)/4
= -27/4
<em>Hence the required value is -27/4</em>
Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
To rearrange you must first simplify
aq-ac=d
add ac to each side:
aq=d+ac
then divide by a:
q=(d/a)+c and this is your answer
The correct anwer is option C and option E which are √4<√5<√√55 and √8<2.9<√√9.
<h3>What is inequality?</h3>
Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.
The two inequalities √4<√5<√√55 and √8<2.9<√√9. are true.
√4<√5<√√55 → 2 < 2.23 < 7.41
√8<2.9<√√9 → 2.82 < 2.9 < 3
Therefore correct answers is option C and option E which are √4<√5<√√55 and √8<2.9<√√9.
To know more about inequality follow
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We are to find how long will it take to return to the ground?
Answer:
t = 0.48 sec
Step-by-step explanation:
We are given;
initial velocity; vi = 40 ft/s
hi = 70 ft
acceleration due to gravity; a = 32 ft/s²
Now, we are given that the rocket's height as a function of time is;
h = -12at² + vit + hi
At ground, h = 0
Plugging in the relevant values to obtain ;
0 = -12(32)t² + 40t + 70
-384t² + 40t + 70 = 0
The roots of the equation gives; t = 0.48 sec