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8090 [49]
3 years ago
7

During one month of cell phone use, Noah used 200 anytime minutes and 400 text messages, and paid $80.00. The next month, he use

d 150 anytime minutes and 350 text messages, and paid $67.50. Which statement is true? Each text message costs 5 cents more than each anytime minute. Each anytime minute costs 10 cents more than each text message. A text message and an anytime minute each cost 25 cents. Each text message costs double the amount of an anytime minute.

Mathematics
2 answers:
saw5 [17]3 years ago
6 0

Answer:

A

Step-by-step explanation:

Troyanec [42]3 years ago
5 0
200x+400y=80
150x+350y=67.5

200x+400y=80
200x=80-400y
x=0.4-2y
150(0.4-2y)+350y=67.5
60-300y+350y=67.5
50y=7.5
y=0.15 or 15 cents per text
200x+400y=80
200x+400(0.15)=80
200x+60=80
200x=20
x=0.1 or 0.10 per minute
So each text costs 5 cents more than each anytime minute

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If a and B are the zeros of the quadratic polynomial f(x) = x2- 5x + 4 find the value of 1/a+1/b-2ab
bearhunter [10]

Answer:

<h2>-27/4</h2>

Step-by-step explanation:

Given the quadratic polynomial given as g(x) = x²- 5x + 4, the zeros of the quadratic polynomial occurs at g(x) = 0 such that x²- 5x + 4 = 0.

Factorizing the resulting equation to get the roots

x²- 5x + 4 = 0

(x²- x)-(4 x + 4) = 0

x(x-1)-4(x-1) = 0

(x-1)(x-4) = 0

x-1 = 0 and x-4 = 0

x = 1 and x = 4

Since a and b are known to be the root then we can say a = 1 and b =4

Substituting the given values into the equation  1/a+1/b-2 ab , we will have;

= 1/1 + 1/4 - 2*1*4

= 1 + 1/4 - 8

= 5/4 - 8

Find the Lowest common multiple

= (5-32)/4

= -27/4

<em>Hence the required value is -27/4</em>

5 0
4 years ago
dale has a square garden. He adds a 2-foot-wide walkway around his garden. If the total area of the walkway and garden is 196 sq
dem82 [27]
Let the side of the garden alone (without walkway) be x.  
Then the area of the garden alone is x^2.  
The walkway is made up as follows:

1) four rectangles of width 2 feet and length x, and 
 2) four squares, each of area 2^2 square feet.


The total walkway area is thus x^2 + 4(2^2) + 4(x*2).  

We want to find the dimensions of the garden.  To do this, we need to find the value of x.

Let's sum up the garden dimensions and the walkway dimensions:

x^2 + 4(2^2) + 4(x*2) = 196 sq ft

x^2 + 16 + 8x = 196 sq ft

x^2 + 8x - 180 = 0

(x-10(x+18) = 0

x=10 or x=-18.  We must discard x=-18, since the side length can't be negative.  We are left with x = 10 feet.

The garden dimensions are (10 feet)^2, or 100 square feet.


4 0
3 years ago
Rearrange a (q-c)=d to make q the subject
Andrej [43]
To rearrange you must first simplify
aq-ac=d  
add ac to each side:
aq=d+ac
then divide by a:
q=(d/a)+c and this is your answer
3 0
3 years ago
Which inequalities are true? Select the four correct answers.
tiny-mole [99]

The correct anwer is option C and option E which are √4<√5<√√55 and √8<2.9<√√9.

<h3>What is inequality?</h3>

Inequality is the relationship between two expressions that are not equal, employing a sign such as ≠ “not equal to,” > “greater than,” or < “less than.”.

The two inequalities √4<√5<√√55 and √8<2.9<√√9. are true.

√4<√5<√√55  → 2 < 2.23 < 7.41

√8<2.9<√√9    → 2.82 < 2.9 < 3

Therefore correct answers is option C and option E which are √4<√5<√√55 and √8<2.9<√√9.

To know more about inequality follow

brainly.com/question/24372553

#SPJ1

6 0
2 years ago
Round numerical answers to the nearest hundredth, if necessary.
MAXImum [283]

We are to find how long will it take to return to the ground?

Answer:

t = 0.48 sec

Step-by-step explanation:

We are given;

initial velocity; vi = 40 ft/s

hi = 70 ft

acceleration due to gravity; a = 32 ft/s²

Now, we are given that the rocket's height as a function of time is;

h = -12at² + vit + hi

At ground, h = 0

Plugging in the relevant values to obtain ;

0 = -12(32)t² + 40t + 70

-384t² + 40t + 70 = 0

The roots of the equation gives; t = 0.48 sec

6 0
3 years ago
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