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vichka [17]
2 years ago
10

I POSTED THIS 3 TIMES AND NOBODY HELPED ME STILL?? :((( PLS HELP

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
4 0

Answer:

the first one

Step-by-step explanation:

angle L congruent to angle P

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Write an integer for each situation.(In this exercise you must Wirte the + and Negative signs) 1.) A profit of $12 2.) 1,440 fee
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1)  + $12, since it is a profit

2) -1440 ft,  since it is below the sea level

3) - 22°F,    since it is below

4) + 31 yards,  since it is a gain.
7 0
3 years ago
What value of c makes x2 − 12x + c a perfect square trinomial? −36 −24 24 36
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Take half of the middle coefficient.
Then square it.

-12/2 = -6

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16^1/4 = <br> a. 1/2<br> b. 2<br> c. 4
stiv31 [10]

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Step-by-step explanation:

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3 years ago
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Two ships leave a harbor together, traveling on courses that have an angle of 135°40' between them. If they each travel 402 mile
mario62 [17]

Answer:

Therefore they are 734.106 miles apart.

Step-by-step explanation:

Given that ,

Two ships have a harbor together. The angle between two ships  is  135°40'. Each of two ships travel 402 miles.

It forms a isosceles triangle whose two sides are 402 miles and one angle is 135°40'. Since it is isosceles triangle then other two angles of the triangle is equal.

Let ∠B= 135°40', and AB = 402 miles , BC =  402 miles

Then the distance between the ships = AC

We know

The sum of all angles = 180°

⇒∠A+∠B+∠C=180°

⇒∠A+135°40'+∠C=180°

⇒2∠A= 180°- 135°40'      [ since ∠A=∠C]

⇒2∠A=44°60'

⇒∠A= 22°30'

Again we know that,

\frac{AB}{sin\angle C}=\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Taking last two ratio,

\frac{BC}{sin \angle A}=\frac{AC}{sin \angle B}

Putting the value of BC , AC ,∠A,∠B

\frac{402}{sin 22^\circ30'}=\frac{AC}{sin 135^\circ40'}

\Rightarrow AC=\frac{402 \times sin135^\circ40'}{sin 22^\circ30'}

         ≈734.106 miles

Therefore they are 734.106 miles apart.

3 0
3 years ago
Thanks for help have nice day
kupik [55]

Answer: 6. d

7. b

8. d

9. c

Step-by-step explanation:

8 0
3 years ago
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