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3 years ago

I POSTED THIS 3 TIMES AND NOBODY HELPED ME STILL?? :((( PLS HELP

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

4 0

Answer:

the first one

Step-by-step explanation:

angle L congruent to angle P

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Answer:

8.49 inches

Step-by-step explanation:

x^2 + 7^2 = 11^2

x^2 + 49 = 121

X^2 = 121 - 49

x^2 = 72 (then take square root on both sides)

x = 8.49 inches

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3 years ago

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lozanna [386]

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2 years ago

Prove that a triangle with the sides a - 1 cm to root under a

vivado [14]

Question is Incomplete, Complete question is given below.

Prove that a triangle with the sides (a − 1) cm, 2√a cm and (a + 1) cm is a right angled triangle.

Answer:

∆ABC is right angled triangle with right angle at B.

Step-by-step explanation:

Given : Triangle having sides (a - 1) cm, 2√a and (a + 1) cm.

We need to prove that triangle is the right angled triangle.

Let the triangle be denoted by Δ ABC with side as;

AB = (a - 1) cm

BC = (2√ a) cm

CA = (a + 1) cm

Hence,

${AB}^2 = (a -1)^2$

Now We know that

$(a- b)^2 = a^2+b^2 - 2ab$

So;

${AB}^2= a^2 + 1^2 -2\times a \times1$

${AB}^2 = a^2 + 1 -2a$

Now;

${BC}^2 = (2\sqrt{a})^2= 4a$

Also;

${CA}^2 = (a + 1)^2$

Now We know that

$(a+ b)^2 = a^2+b^2 + 2ab$

${CA}^2= a^2 + 1^2 +2\times a \times1$

${CA}^2 = a^2 + 1 +2a$

${CA}^2 = AB^2 + BC^2$

[By Pythagoras theorem]

$a^2 + 1 +2a = a^2 + 1 - 2a + 4a\\\\a^2 + 1 +2a= a^2 + 1 +2a$

Hence, ${CA}^2 = AB^2 + BC^2$

Now In right angled triangle the sum of square of two sides of triangle is equal to square of the third side.

This proves that ∆ABC is right angled triangle with right angle at B.

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3 years ago

Help please... ... . . . ...?

MatroZZZ [7]

S represents the best distance from 1 and 0 to represent 33 1/3%

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3 years ago

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