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Natasha_Volkova [10]
3 years ago
15

Fahim is 6 feet tall. At noon, he stands with the sun behind him casting a shadow. The distance from the top of Fahim's head to

the furthest tip of the shadow is 13 feet. A right triangle with side length 6 feet, s, and hypotenuse 13 feet. [Not drawn to scale] What is the length of Fahim's shadow? Round to the nearest tenth of a foot. 7.0 feet 8.5 feet 11.5 feet 14.3 feet
Mathematics
2 answers:
kupik [55]3 years ago
4 0

Answer: 11.5 feet

Step-by-step explanation:

We should note that for a right angles triangle, the square of the hypothenuse equals to the square of the opposite side and its adjacent. This can be expressed as:

Let the length of Fahims shadow be x

hypotenuse² = opposite² + adjacent ²

13² = 6² + x²

169 = 36 + x²

x² = 169 - 36

x² = 133

x =✓133

x = 11.53

= 11.5 feet to nearest tenth

IrinaVladis [17]3 years ago
4 0

Answer:

11.5 feet

Step-by-step explanation:

Fahim been drinkin up on tht pediasure ain he.

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Last Wednesday, a random sample of 24 students were surveyed to find how long it takes to walk from the Fretwell Building to the
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Answer:

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Step-by-step explanation:

Solution:-

- We are to investigate the confidence interval of 95% for the population mean of walking times from Fretwell Building to the college of education building.

- The survey team took a sample of size n = 24 students and obtained the following results:

                Sample mean ( x^ ) = 12.3 mins

                Sample standard deviation ( s ) = 3.2 mins

- The sample taken was random and independent. We can assume normality of the sample.

- First we compute the critical value for the statistics.

- The z-distribution is a function of two inputs as follows:

  • Significance Level  ( α / 2 ) = ( 1 - CI ) / 2 = 0.05/2 = 0.025

Compute: z-critical = z_0.025 = +/- 1.96

- The confidence interval for the population mean ( u ) of  walking times is given below:

                      [ x^ - z-critical*s / √n  ,   x^ + z-critical*s / √n  ]

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3 years ago
Please Help !!Mr. Mudd gives each of his children $2000 to invest as part of a friendly family competition. The competition will
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Answer:

Albert = $2159.07; Marie = $2244.99; Hans = $2188.35; Max = $2147.40

Marie is $10 000 richer

Step-by-step explanation:

Albert

(a) $1000 at 1.2 % compounded monthly

A = P\left(1 + \dfrac{r}{n}\right)^{nt}

A = 1000(1 + 0.001)¹²⁰ = $1127.43

(b) $500 losing 2%

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(c) $500 compounded continuously at 0.8%

\begin{array}{rcl}A & = & Pe^{rt}\\& = & 500e^{0.008 \times 10}\\& = &\mathbf{\$541.64}\\\end{array}\\

(d) Balance

Total = 1127.43 + 490.00+ 541.64 = $2159.07

Marie

(a) 1500 at 1.4 % compounded quarterly

A = 1500(1 + 0.0035)⁴⁰ = $1724.99

(b) $500 gaining 4 %

1.04 × 500 = $520.00

(c) Balance

Total = 1724.99 + 520.00 = $2244.99

Hans

$2000 compounded continuously at 0.9 %

\begin{array}{rcl}A& = &2000e^{0.009 \times 10}\\& = &\mathbf{\$2188.35}\\\end{array}\\

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(c) Balance

Total = 951.11 + 1196.29 = $2147.40

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