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4 years ago

How are they similar?

Mathematics

1 answer:

Verizon [17]4 years ago

4 0

Answer:

By AA similarity

Step-by-step explanation:

In triangle JIK and MJK

angles k=k(Common)

angles JIK = MJK (Both 90 degrees)

in triangles MIJ and MJK

angle m=m common

angles MIJ=MJK

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zlopas [31]

Answer:

The direction angle of vector v is equal to $9.5\°$

Step-by-step explanation:

Let

$A(-5,0),B(7,2)$

The vector v is given by

$v=B-A$

$v=(7, 2) - (-5, 0)$

$v=((7 - (- 5)), (2-0))$

$v=(12, 2)$

Remember that

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substitute the values

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3 years ago

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How do you do this question?

Andrei [34K]

Answer:

Solution : Option B, or 9π

Step-by-step explanation:

We are given that y = x, x = 3, and y = 0.

Now assume we have a circle that models the given information. The radius will be x, so to determine the area of that circle we have πx². And knowing that x = 3 and y = 0, we have the following integral:

$\int _0^3$

So our set up for solving this problem, would be such:

$\int _0^3x^2\pi \:$

By solving this integral we receive our solution:

$\int _0^3x^2\pi dx,\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=> \pi \cdot \int _0^3x^2dx\\\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1}\\=> \pi \left[\frac{x^{2+1}}{2+1}\right]^3_0\\=> \pi \left[\frac{x^3}{3}\right]^3_0\\\mathrm{Compute\:the\:boundaries}: \left[\frac{x^3}{3}\right]^3_0=9\\\mathrm{Substitute:9\pi }$

As you can tell our solution is option b, 9π. Hope that helps!

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3 years ago

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