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Nataly_w [17]
3 years ago
9

Hi! Just need help with the problem below, tysm!

Mathematics
1 answer:
Fynjy0 [20]3 years ago
5 0

"Definition of direct variation. 1 : mathematical relationship between two variables that can be expressed by an equation in which one variable is equal to a constant times the other."

The answer is D

All of the other relationships are consistent.

A is x × 3

B is x × 4

C is x × 2

D is x × 2 then 3 then 4.

D is not a direct variation.

Let me know if you have questions about my answer! :)

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‼️help please thank you ☺️
Kay [80]
The answer is true...
4 0
3 years ago
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The drama club spent $336 on T-shirts if each t-shirt cost $12 how many t-shirts did the drama club buy? what strategy would be
mr_godi [17]

Answer:

28 t-shirts

Step-by-step explanation:

x = # of t-shirts

12x = 336

x = 28

3 0
3 years ago
Please help me I don’t understand
postnew [5]

Answer:

$70

Step-by-step explanation:

If the account start with $95, and you deposited $15:

95+15 = $110

After that, you took 65:

110 -65 = $45

After you deposited $40:

45 + 40 = $85

And for last you took more 15:

85 -15 = $70

5 0
2 years ago
Complete the square x^2+45=-14x
Rom4ik [11]

2
+
4
5
=
−
1
4

x
2
+
45
=
−
14
x
x2+45=−14x

2
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4
5
−
−
1
4

=
0
8 0
3 years ago
Jerome burns 4 cal/min walking and 10 cal/min running. He walks between 10 and 20 min each day and runs between 30 and 45 min ea
erik [133]

Answer:

20 minutes should spend on walking and 30 minutes on running.

Step-by-step explanation:

Let x represents the minutes spent on walking and y represents the minutes spent on running,

∵ He burns 4 cal/min walking and 10 cal/min running,

So, the total calories burnt,

Z = 4x + 10y

Which has to be maximised.

Now, he walks between 10 and 20 min each day,

i.e. 10 < x < 20,

Also, he runs between 30 and 45 min each day,

i.e. 30 <  y < 45,

By graphing 10 < x < 20 and 30 <  y < 45,

We obtained the vertices of feasible region,

(10, 45), (20, 45), (10, 30) and (20, 30)

At (10, 45),

Z = 4(10) + 10(45) = 40 + 450 = 490,

At (20, 45),

Z = 4(20) + 10(45) = 80 + 450 = 530,

At (10, 30),

Z = 4(10) + 10(30) = 40 + 300 = 340,

At (20, 30)

Z = 4(20) + 10(30) = 80 + 300 = 380

Hence, maximum calories is 530 when 20 minutes spent on walking and 30 minutes spent on running.

5 0
3 years ago
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