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Katyanochek1 [597]
3 years ago
12

Find the value of x for which m parallel to n

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
3 0
3x - 36 + 2x + 26 = 180
5x - 10 = 180
5x = 180 + 10
5x = 190
x = 190/5
x = 38 <==
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Determine the quotient of 1 and 2 over 3 divided by 4 over 5.
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The answer to your question is 20/9
7 0
3 years ago
Help me plz I am stuck on this
Temka [501]

Answer:

30 I think

Step-by-step explanation:

5 0
3 years ago
Peter won £75 as a prize.He gave 4/5 of the prize money as a present to Roger and Bethan.Roger and Bethan shared the present in
Molodets [167]
Roger: $24
Bethan: $36

Explanation:
4/5 of $75 is $60

So $60 is distributed to Roger and Bethan in the ratio 2 : 3.

Add the numbers in the ratio 2 : 3
2 + 3 = 5

Divide $60 by 5
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Multiply each number in the ratio 2 : 3 by 12:
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7 0
2 years ago
Solve: (2x - 3)^2 = -4
Wewaii [24]

Answer:

No real solutions;

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Step-by-step explanation:

The easiest method to solve an algebraic equation is to use inverse operations. This applies to the given equation;

(2x-3)^2=-4\\

- Take the square root of both sides

\sqrt{}                

==================================================================

As one can see, the right side is a negative number. However, one cannot take the square root of a negative number and get a real result. Therefore, one must use imaginary numbers. Remember, the imaginary unit (i) represents (\sqrt{-1}).

==================================================================

2x-3=2i

- Add (3) to undo the (-3)

+3          

2x=2i+3

- Divide by (2) to remove the coefficient of (2x)

÷2           ÷

x=\frac{2i+3}{2}

Simplify,

x=i+1.5

6 0
2 years ago
Find the fifth term of the geometric sequence whose first term is 81 and whose common ratio is 1/3.(1 point)13
Ludmilka [50]

n^{th}\textit{ term of a geometric sequence} \\\\ a_n=a_1\cdot r^{n-1}\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{5}\\ a_1=\stackrel{\textit{first term}}{81}\\ r=\stackrel{\textit{common ratio}}{\frac{1}{3}} \end{cases}\implies a_5=81\left( \cfrac{1}{3} \right)^{5-1} \\\\\\ a_5=81\left( \cfrac{1}{3} \right)^4\implies a_5=81\cdot \cfrac{1}{81}\implies a=1

7 0
1 year ago
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