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The given question is incomplete. The complete question is as follows;
The number of bacteria in a certain population is predicted to increase according to a continuous exponential growth model, at a relative rate of 16% per hour. Suppose that a sample culture has an initial population of 71 bacteria. Find the predicted population after three hours Do not round any intermediate computations, and round your answer to the nearest tenth bacteria
.
Answer:
114.7
Explanation:
A (t) represent the population of the bacteria at the time t.
Since, the population grows exponentially, the population can be calculated as follows:
A (t) = Ao × 
A (t) is teh final population, Ao is the initial population, e is the exponential, k is rate and t is time.
A (t) = 71 × 
For t = 3 hours
A (t) = 71 × 
A (t) = 114.7.
The population of bacteria after 3 hours is 114.7.
<h2>Microbes and ruminants relation</h2>
Explanation:
The mixture of microbes allows the host animal to produce a much wider variety of digestive enzymes, far more than the host could encode in their own genome
- The microbes in the gut of ruminants include bacteria,fungi and protozoa
- These microbes helps the ruminant animals to digest food,without the microbes these animals would die
- The microbes break down feed to produce volatile fatty acids, which are used by the cow(ruminant animal) as energy for maintenance and milk production
3. golgi apparatus
2. rough endoplasmic
1. cytoplasm
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Make a electron cloud and put 2 dots on the first layer and 7 on the outer layer