Question

Rewrite the following without an exponent. (−4)^−2

Answer 1

$\bf a^{-{ n}} \implies \cfrac{1}{a^{ n}}\qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \\ \quad \\ % negative exponential denominator a^{{ n}} \implies \cfrac{1}{a^{- n}} \qquad \qquad \cfrac{1}{a^{- n}}\implies \cfrac{1}{\frac{1}{a^{ n}}}\implies a^{{ n}} \\\\ -------------------------------\\\\ (-4)^{-2}\implies \cfrac{1}{(-4)^2}\implies \cfrac{1}{(-4)(-4)}\implies \cfrac{1}{16}$