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Nataly_w [17]
3 years ago
6

The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5 . Suppose 49 golfers p

layed the course today. Find the probability that the average score of the 49 golfers exceeded 62.
A) .3707

B) .4772

C) .1293

D) .0228
Mathematics
1 answer:
Nadya [2.5K]3 years ago
7 0

Answer:

The probability that the average score of the 49 golfers exceeded 62 is 0.3897

Step-by-step explanation:

The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5

\mu = 61

\sigma = 3.5

We are supposed to find he probability that the average score of the 49 golfers exceeded 62.

Formula : Z=\frac{x-\mu}{\sigma}

Z=\frac{62-61}{3.5}

Z=0.285

Refer the z table for p value

p value = 0.6103

P(x>62)=1-P(x<62)=1-0.6103=0.3897

Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Normal Probability Distribution

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