The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5 . Suppose 49 golfers p
1 answer:
Answer:
The probability that the average score of the 49 golfers exceeded 62 is 0.3897
Step-by-step explanation:
The average score of all golfers for a particular course has a mean of 61 and a standard deviation of 3.5
We are supposed to find he probability that the average score of the 49 golfers exceeded 62.
Formula :
Refer the z table for p value
p value = 0.6103
P(x>62)=1-P(x<62)=1-0.6103=0.3897
Hence the probability that the average score of the 49 golfers exceeded 62 is 0.3897
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