vertex (1,-1) axis of symmetry is x=1, domain all real numbers (i think neg ys) range y is less equal than -1, y increases as x less 0 bug IMO x decreases
Answer:
the best value is two 50 ml bottles
Step-by-step explanation:
Okay focus with me , if you buy a bottle of 50 ml you will get a second for half price so we can say that --> 2 bottles of 50 ml =
We get 100 ml with £67.5 just , but when you buy 80ml you must pay £55 Hum !
then you can dived the volume of bottle with price ...
- the price of one ml is 0.675 in first State
- in the second state the price of one ml is
then :
so the best value is two 50 ml bottles
The amount of money that John would have in his account when he is ready to retire is $6,351,400.21.
<h3>How much would be in the retirement account?</h3>
The formula that can be used to determine the future value of the annuity is
Future value = Daily deposit x annuity factor
Annuity factor = {[(1+r)^n] - 1} / r
Where:
- r = 3.5 / 365 = 0.0096%
- n = (65 - 48) x 365 = 6205
Annuity factor = [(1.000096^6205) - 1] / 0.000096 = $8468.53
Future value = 750 x $8468.53 = $6,351,400.21
To learn more about annuities, please check: brainly.com/question/24108530
#SPJ1
We start by ordering the values.
5, 7, 8, 10, 13, 14, 17, 17, 21
Now we find the median(middle number).
Median(b): 13
(I added (b) for "base" since we need to take more medians)
The median now divides this data into two halves.
Now we take the medians of the two remaining halves.
Median(Half1): 7.5
Median(Half2): 17
Mark off the minimum and maximum.
Min: 5
Max: 21
Now graph!
Your median(Half1) is incorrect, since your median for the first half is 9. Since our median for the first half is 7.5, the answer would be Answer Choice C.
Answer:
a) Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
b) If the true mean is 190 days, Type II error can be made.
Step-by-step explanation:
Let mu be the mean life of the batteries of the company when it is used in a wireless mouse
Null and alternative hypotheses are:
: mu=183 days
: mu>183 days
Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.
That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.