Answer: (P.s its very hard to write special characters here, i hope this helped though)
((−6d0)(g−3))(h2)
d−5m3g−2h5
=
−6d5g2h2
g3h5m3
=
−6d5
gh3m3
Answer:
Given:
I usually walk from home to work. This morning, I walked for 10 minutes until I was halfway to work.
I then realized that I would be late if I kept walking.
I ran the rest of the way. I run twice as fast as I walk.
Find:
The number of minutes in total did it take me to get from home to work
Step-by-step explanation:
Had I kept walking, the second half of my trip would have taken 10 more minutes.
By doubling my speed for the second half of my trip,
I halved the amount of time it took me to finish.
So, the second half of my trip took 5 minutes, for a total trip time of 10+5 = 15 minutes.
The number of minutes in total did it take me to get from home to work is 15 minutes.
Area of the board divided by the time
2 x 3 = 6ft^2
15/6= 2.5mins
B. j = 32m
Hope this helps!
You combine those variables, then solve.
hope that helps :) ✨