(10 points) A stopwatch has three states named Zero, Running, and Stopped. There are two buttons, named B1 and B2. For each butt
on, pressing the button produces a 1 and not pressing the button produces a 0. B1 works as follows: If the stopwatch is in the Zero state, pressing B1 causes it to advance to the Running state. If the stopwatch is in the Running state, pressing B1 causes it to advance to the Stopped state. If the stopwatch is in the Stopped state, pressing B1 causes it to return to the Running state. Pressing B2 has no effect unless the stopwatch is in the Stopped state, in which case pressing B2 (even if B1 is pressed) causes the stopwatch to go to the Zero state. Design a finite state machine controller for this stopwatch that has two inputs (B1 and B2) and three outputs, one for each of the three states. The state of the controller uses two J-K flip-flops.
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Answer:
Check the explanation
Explanation:
CODE:
#include <iostream>
#include <iomanip>
using namespace std;
double getLoanAmount() { // functions as per asked in question
double loan;
while(true){ // while loop is used to re prompt
cout << "Enter the car loan amount ($2,500-7,500): ";
cin >> loan;
if (loan>=2500 && loan <= 7500){ // if the condition is fulfilled then
break; // break statement is use to come out of while loop
}
else{ // else error message is printed
cout << "Error: $"<< loan << " is an invalid loan amount." << endl;
}
}
return loan;
}
double getMonthlyPayment(){ // functions as per asked in question
double monthpay;
while(true){ // while loop is used to re prompt
cout << "Enter the monthly payment ($50-750): ";
cin >> monthpay;
if (monthpay>=50 && monthpay <= 750){ // if the condition is fulfilled then
break; // break statement is use to come out of while loop
}
else{ // else error message is printed
cout << "Error: $"<< monthpay << " is an invalid monthly payment." << endl;
}
}
return monthpay;
}
double getInterestRate(){ // functions as per asked in question
double rate;
while(true){ // while loop is used to re prompt
cout << "Enter the annual interest rate (1-6%): ";
cin >> rate;
if (rate>=1 && rate <= 6){ // if the condition is fulfilled then
break; // break statement is use to come out of while loop
}
else{ // else error message is printed
cout << "Error: "<< rate << "% is an invalid annual interest rate." << endl;
}
}
return rate;
}
int main() {
cout << setprecision(2) << fixed; // to print with 2 decimal places
int month = 0; // initializing month
// calling functions and storing the returned value
double balance= getLoanAmount();
double payment= getMonthlyPayment();
double rate= getInterestRate();
rate = rate /12 /100; // as per question
// printing as per required in question
cout << "Month Balance($) Payment($) Interest($) Principal($)"<< endl;
while(balance>0){ // while the balance is more than zero
month = month + 1; // counting Months
// calculations as per questions
double interest = balance * rate;
double principal = payment - interest;
balance = balance - principal;
// printing required info with proper spacing
cout <<" "<< month;
cout <<" "<< balance;
cout <<" "<< payment;
cout <<" "<< interest;
cout <<" "<< principal << endl;
}
cout << "Months to repay loan: " << month << endl; // displaying month
cout << "End of Banker Bisons";
Kindly check the output in the attached image below.
