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pantera1 [17]
3 years ago
13

(10 points) A stopwatch has three states named Zero, Running, and Stopped. There are two buttons, named B1 and B2. For each butt

on, pressing the button produces a 1 and not pressing the button produces a 0. B1 works as follows: If the stopwatch is in the Zero state, pressing B1 causes it to advance to the Running state. If the stopwatch is in the Running state, pressing B1 causes it to advance to the Stopped state. If the stopwatch is in the Stopped state, pressing B1 causes it to return to the Running state. Pressing B2 has no effect unless the stopwatch is in the Stopped state, in which case pressing B2 (even if B1 is pressed) causes the stopwatch to go to the Zero state. Design a finite state machine controller for this stopwatch that has two inputs (B1 and B2) and three outputs, one for each of the three states. The state of the controller uses two J-K flip-flops.

Computers and Technology
1 answer:
solniwko [45]3 years ago
6 0

Answer:

see explaination

Explanation:

State Diagram based on given in the problem and state table, k-map for j and k, based j and k expressions we can draw the (FSM )controller using j and j flip flop.

see attachment for this.

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Answer:

The GREEDY Algorithm

Explanation:

Based on the situation given in question, the Greedy algorithm shall give the optimal solution to professor

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This can be written as ;

G=g1, g2, . . . , gk

Z=z1, z2, . . . , zk’

Here k’ <= k and k < n

Let I be an idex where for the first time gi is not equal to zi

Considering t= maxi Zi

Z′=g1, z2, z3, . . . , zk′

Now since z2, z3, . . . , zk′ should be an optimal stopping pattern for the problem otherwise we have chosen Z, with smaller gas filling (not feasible)

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