It already is a decimal unless you mean a repeating decimal, it would be .26 with a line over the number.
Answer:
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
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This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))
(1) <span>The surface area of the square pyramid = 4 * (area of one face) + area of the base
area of one face = 0.5 * 34.2 * 28.4
area of the base = 34.2 * 34.2
∴ </span>The surface area of the pyramid = 4 * (<span>0.5 * 34.2 * 28.4) + </span><span>34.2 * 34.2
By comparing the last answer with the answer of </span>Vikram, we find that:
He used the wrong expression to represent the area of the base of the pyramid.
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(2) The surface area of the rectangular pyramid
= area of two face with the height 36.5 + area of two face with the height 37.8 + area of the base
area of two face with the height 36.5 = 2 * 0.5 * 36.5 * 25.6
area of two face with the height 37.8 = 2 * 0.5 * 37.8 * 16.2
are of the base = 25.6 * 16.2
Total area = (2 * 0.5 * 36.5 * 25.6) + (2 * 0.5 * 37.8 * 16.2) + (25.6 * 16.2)
= (36.5 * 25.6) + (37.8 * 16.2) + (25.6 * 16.2)
note: 2 *0.5 = 1
By comparing the last answer with the answer of Tracy , we find that:
<span>Tracy’s answer will be correct because she made use of the fact that 2 (1/2) = 1 in her expression.
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</span>
(3)
the total surface area of this rectangular pyramid =
= area of two face with the height 52 + area of two face with the height 60 + area of the base
area of two face with the height 52 = 2 * 0.5 * 52 * 78 = 4,056 m²
area of two face with the height 60 = 2 * 0.5 * 60 * 50 = 3,000 m²
are of the base = 78 * 50 = 3900 m²
Total area = 4,056 + 3,000 + 3,900 = 10,956 m²
