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Anastasy [175]
3 years ago
8

I need help with number 3 and 4. Please

Mathematics
1 answer:
noname [10]3 years ago
6 0

For #3 the slop is 4/3 .

The y intercept is -5.

So the equation is

y=4/3x -5

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Answer:

  x = 4

Step-by-step explanation:

The vertex is on the line of symmetry. The zeros are located equidistant from the line of symmetry, which is ...

  x = (2 + 6)/2 = 4

The x-coordinate of the vertex is x=4.

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Drag each number to the correct location on the table.
ASHA 777 [7]

Answer:

\text{Rational number} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{ Irrational number}

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Step-by-step explanation:

Since we believe it  

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Answer:

4.4%

Step-by-step explanation:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

​  

)  

nt

 

Compound interest formula

A=11700\hspace{35px}P=6900\hspace{35px}t=12\hspace{35px}n=365

A=11700P=6900t=12n=365

Given values

11700=

11700=

\,\,6900\left(1+\frac{r}{365}\right)^{365(12)}

6900(1+  

365

r

​  

)  

365(12)

 

Plug in values

11700=

11700=

\,\,6900\left(1+\frac{r}{365}\right)^{4380}

6900(1+  

365

r

​  

)  

4380

 

Multiply

\frac{11700}{6900}=

6900

11700

​  

=

\,\,\frac{6900\left(1+\frac{r}{365}\right)^{4380}}{6900}

6900

6900(1+  

365

r

​  

)  

4380

 

​  

 

Divide by 6900

1.695652174=

1.695652174=

\,\,\left(1+\frac{r}{365}\right)^{4380}

(1+  

365

r

​  

)  

4380

 

\left(1.695652174\right)^{1/4380}=

(1.695652174)  

1/4380

=

\,\,\left[\left(1+\frac{r}{365}\right)^{4380}\right]^{1/4380}

[(1+  

365

r

​  

)  

4380

]  

1/4380

 

Raise both sides to 1/4380 power

1.000120571=

1.000120571=

\,\,1+\frac{r}{365}

1+  

365

r

​  

 

-1\phantom{=}

−1=

\,\,-1

−1

Subtract 1

0.000120571=

0.000120571=

\,\,\frac{r}{365}

365

r

​  

 

365\left(0.0001206\right)=

365(0.0001206)=

\,\,\left(\frac{r}{365}\right)365

(  

365

r

​  

)365

Multiply by 365

0.044008415=

0.044008415=

\,\,r

r

4.4008415\%=

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Answer:

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Plug in the value of x

12(12) - 28

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= 116°

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7(12) + 32

= 84 + 32

= 116°

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3 years ago
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