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On the basis of the given unbalanced equation, that is:
HBr (aq) + 2NaOH (aq) → 2NaBr (s) + H2O (l)
On the right side of the equation, there are 2 atoms of sodium (Na), 2 atoms of bromine (Br), 2 atoms of hydrogen (H), and 1 atom of oxygen (O₂).
After balancing the equation correctly we get:
HBr (aq) + NaOH (aq) → NaBr (s) + H2O (l)
On the right side, one atom of Na, 1 atom of Br, 1 atom of H and one atom of O₂.
Answer:
The value of
at 4224 K is 314.23.
Explanation:

Initially
4.97 atm 0
At equilibrium
4.97 - p 2p
At initial stage, the partial pressure of oxygen gas = =4.97 atm
At equilibrium, the partial pressure of oxygen gas = 
So, 4.97 - p = 0.28 atm
p = 4.69 atm
At equilibrium, the partial pressure of O gas = 
The expression of
is given as :


The value of
at 4224 K is 314.23.