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Veseljchak [2.6K]
2 years ago
12

HELP PLS ITS URGENT what is the energy of a photon of a red light? red: 6.50x10^-7m

Chemistry
1 answer:
MatroZZZ [7]2 years ago
8 0

Answer:

I think the answer is is 4.62x10^14 s-1

Explanation:

Sorry if it is wrong

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Calculate the Cal(kcal) in 1 cup of whole milk: 12 g of carbohydrate, 9 g of fat, and 9 g of protein.
laiz [17]
 Fat: 1 gram = 9 calories    Protein: 1 gram = 4 calories    Carbohydrates: 1 gram = 4 calories    Alcohol: 1 gram = 7 calories"
So, (12 g carbohydrates)*4 Cal=48 Cal; (9 g fat) *9 Cal=81 Cal; (9 g protein)*4 Cal=36 Cal
48 Cal + 81 Cal + 36 Cal = 165 Cal in one glass of milk
5 0
4 years ago
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What is the correct name for this formula: BaCl2
Inessa05 [86]
BaCI2 stands for Barium Chloride. Hope this helps!
3 0
3 years ago
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All people who are asked to testify in a criminal case must first be issued a subpoena by law enforcement.
BigorU [14]

Answer:

Option B

Explanation:

All people who are asked to testify in a criminal case must first be issued a subpoena by law enforcement, is a "false statement" or option B. A subpoena is a request to appear in court which is usually given out by the attorneys who are a part of the case, the law enforcement does not give out subpoenas, so this is indeed a false statement.

Hope this helps.

7 0
3 years ago
What are the coefficients for the following equation when it is balanced?
konstantin123 [22]
1, 2, 1, 2, in that order.
3 0
3 years ago
Anyone? Please help
snow_tiger [21]

Answer:

The limiting reacting is O2

Explanation:

Step 1: data given

Number of moles O2 = 21 moles

Number of moles C6H6O = 4.0 moles

Step 2: The balanced equation

C6H6O + 7O2 → 6CO2 + 3H2O

Step 3: Calculate the limiting reactant

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed (21 moles).

C6H6O is in excess.

For 7 moles O2 we need 1 mol C6H6O

For 21 moles O2 we'll need 21/7 = 3 moles C6H6O

There will remain 4.0 - 3.0 = 1 mol C6H6O

Step 4: calculate products

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2

For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O

The limiting reacting is O2

7 0
4 years ago
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