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12345 [234]
2 years ago
6

Assume that you measured exactly 2.0 mL of the sodium chloride solution into a small test tube. How many moles of

Chemistry
1 answer:
erik [133]2 years ago
7 0
The are about 89 miles of sodium chloride in the tube.
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Assume that Na+ is being transported across a membrane via facilitated diffusion. Which of the following conditions would allow
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Answer:

<h2>4. Na+ diffusing toward the side of the membrane with Cl− and 50% less Na+.</h2>

Explanation:

Facilitated diffusion is a type of transport mechanism in which the special proteins are involved and play an important role in the transport of the atoms, ions or molecules. This mechanism is based on the electrochemical gradient differences. When this difference increase, then the transport of the sodium takes place because sodium ions are chemically attracted by chloride ions. In a facilitated diffusion process, no energy requirement takes place. This process occurs along the concentration gradient.

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Use the table on the right to calculate each required quantity.
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a. 35.8 KJ

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Suppose a student did not fully redissolve the Al(OH)3 that initially formed upon the addition of H2SO4. Predict and explain how
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3 years ago
Barium nitrate and sodium sulfate solutions can be used to precipitate barium sulfate. How many grams
-Dominant- [34]

Answer:

40.8g of sodium sulfate must be added

Explanation:

The reaction of barium nitrate, Ba(NO₃)₂ with sodium sulfate, Na₂SO₄ is:

Ba(NO₃)₂ + Na₂SO₄ → 2 NaNO₃ + BaSO₄(s)

That means, for a complete reaction of an amount of barium nitrate you must add the same amount in moles of sodium sulfate. To solve this problem we need to convert the mass of barium nitrate to moles = Moles of sodium sulfate that must be added:

<em>Moles Ba(NO₃)₂ -Molar mass: 261.3g/mol-:</em>

75g * (1mol / 261.3g) = 0.287 moles = Moles Na₂SO₄

<em>Mass Na₂SO₄ -Molar mass: 142.04g/mol-:</em>

0.287 moles * (142.04g / mol) =

<h3>40.8g of sodium sulfate must be added</h3>
7 0
3 years ago
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