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Ainat [17]
2 years ago
12

List the number of each type of atom on the right side of the equation hbr(aq)+2naoh(aq)→2nabr(s)+h2o(l)

Chemistry
2 answers:
ser-zykov [4K]2 years ago
5 0

On the basis of the given unbalanced equation, that is:

HBr (aq) + 2NaOH (aq) → 2NaBr (s) + H2O (l)

On the right side of the equation, there are 2 atoms of sodium (Na), 2 atoms of bromine (Br), 2 atoms of hydrogen (H), and 1 atom of oxygen (O₂).

After balancing the equation correctly we get:

HBr (aq) + NaOH (aq) → NaBr (s) + H2O (l)

On the right side, one atom of Na, 1 atom of Br, 1 atom of H and one atom of O₂.

AlexFokin [52]2 years ago
4 0

Answer:

As per the given unbalanced equation:-

HBr(aq) + 2NaOH(aq) --> 2NaBr(s) + H2O(l)

Na:-2

Br:-2

H:- 2

O:- 1

If correctly balanced then

HBr(aq) + NaOH(aq) --> NaBr(s) + H2O(l)

Na:-1

Br:-1

H:- 2

O:- 1

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30.07 g/mol (that’s grams per mole)
8 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘ 25 ∘ C. Standard enthalpy of formation values can be found in th
WINSTONCH [101]

<u>Answer:</u> The standard enthalpy change of the reaction is coming out to be -16.3 kJ

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. It is represented as \Delta H

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

Mg(OH)_2(s)+2HCl(g)\rightarrow MgCl_2(s)+2H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(1\times \Delta H_f_{(MgCl_2(s))})+(2\times \Delta H_f_{(H_2O(g))})]-[(1\times \Delta H_f_{(Mg(OH)_2(s))})+(2\times \Delta H_f_{(HCl(g))})]

We are given:

\Delta H_f_{(Mg(OH)_2(s))}=-924.5kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol\\\Delta H_f_{(MgCl_2(s))}=-641.8kJ/mol\\\Delta H_f_{(H_2O(g))}=-241.8kJ/mol

Putting values in above equation, we get:

\Delta H_{rxn}=[(1\times (-641.8))+(2\times (-241.8))]-[(1\times (-924.5))+(2\times (-92.30))]\\\\\Delta H_{rxn}=-16.3kJ

Hence, the standard enthalpy change of the reaction is coming out to be -16.3 kJ

6 0
3 years ago
The type of radiation which is identical to a high energy electron is known as a(n). beta, alpha, or gamma particles
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The type of radiation which is identical to a high energy electron is known as a(n) beta.

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Read 2 more answers
+++TO BE ANSWERED ASAP (WILL PUT BRAINLIEST!!!)+++
goldfiish [28.3K]

Answer:

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Explanation:

5 0
2 years ago
Determine the number of moles of C5H12 that are contained in 357.4 g of the compound.
AlladinOne [14]

Answer: 4.96 moles

Explanation:

C5H12 is the chemical formula for pentane, the fifth member of the alkane family.

Given that,

number of moles of C5H12 = ?

Mass in grams = 357.4 g

Molar mass of C5H12 = ?

To get the molar mass of C5H12, use the atomic mass of carbon = 12g; and Hydrogen = 1g

i.e C5H12 = (12 x 5) + (1 x 12)

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Now, apply the formula

Number of moles = Mass / molar mass

Number of moles = 357.4g / 72g/mol

= 4.96 moles

Thus, 4.96 moles of C5H12 that are contained in 357.4 g of the compound.

4 0
3 years ago
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