How do you find the y-intercept for x = 2y2 + 3y + 1
1 answer:
The y intercept is when x=0. That's solving the quadratic
0 = 2y² + 3y + 1 = (2y + 1)(y + 1)
y = -1 or 2y+1=0 so y=-1/2
Two y intercepts, (0,-1) and (0,-1/2)
Answer: -1 and -1/2
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