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Arada [10]
3 years ago
15

Fiona joins a fruit of the month club. The entry cost is $25 and then she pays $18 per month. If she participates for 8 months,

how much will she pay in all?
Mathematics
2 answers:
xeze [42]3 years ago
5 0

Answer: $169

Step-by-step explanation: The expression 25 + 18 x 8 represents the amount she will pay if she participates for 8 months.

Multiply 18 x 8 to find the cost for 8 months. $18 x 8 = $144.

Now add $25 to $144, which equals $169

devlian [24]3 years ago
4 0

Answer: 169

Step-by-step explanation: first off you should note that the entry cost being 25 dollars is a one time thing( it should be the number that you add to the amount she pays for 8 months) The first step is to multiply 18 by 8. This is because she pays $18 per month, for 8 months. the product will be $144. Then you add the entry cost which is $25 which in all comes out to $169.

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One watering system needs about three times as long to complete a job as another warning system when both systems operate at the
algol13

Answer:

One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

Step-by-step explanation:

Given:

Both the system can complete the job = 9 minutes

We need find the time required by each system to do the job.

Solution:

Let the time required by another watering system to complete the job be 'x' mins.

Now given:

One watering system needs about three times as long to complete a job as another watering system.

Time required by one watering system = 3x

Rate to complete the job by another watering system = \frac{1}{x}\ job/min

Rate to complete the job by One watering system = \frac{1}{3x}\ job/min

Rate at which both can complete the job = \frac{1}{9}\ job/min

So we can say that;

Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.

framing in equation form we get;

\frac{1}{x}+\frac{1}{3x}=\frac19

Now taking LCM to make the denominator common we get;

\frac{1\times3}{x\times 3}+\frac{1\times1}{3x\times1}=\frac19\\\\\frac{3}{3x}+\frac{1}{3x}=\frac19\\\\\frac{3+1}{3x}=\frac{1}{9}\\\\\frac{4}{3x}=\frac{1}{9}

By Cross multiplication we get;

4\times9 =3x\\\\3x =36

Dividing both side by 3 we get;

\frac{3x}{3}=\frac{36}{3}\\\\x=12\ min

Time required by One watering system = 3x =3\times 12 =36\ min

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