Given:
The given digits are 1,2,3,4,5, and 6.
To find:
The number of 5-digit even numbers that can be formed by using the given digits (if repetition is allowed).
Solution:
To form an even number, we need multiples of 2 at ones place.
In the given digits 2,4,6 are even number. So, the possible ways for the ones place is 3.
We have six given digits and repetition is allowed. So, the number of possible ways for each of the remaining four places is 6.
Total number of ways to form a 5 digit even number is:
Therefore, total 3888 five-digit even numbers can be formed by using the given digits if repetition is allowed.
Simplified expression is 6y² - 24y - 51. Value for y=-2 is 21 and value for y=3 is -69.
Step-by-step explanation:
- Step 1: Given expression is 3y(2y-7) - 3(y - 4) - 63. Simplify it.
⇒ 6y² - 21y - 3y + 12 - 63
⇒ 6y² - 24y - 51
- Step 2: Find value of the expression for y = -2
⇒ 6y² - 24y - 51 = 6(-2)² - 24(-2) - 51 = 24 + 48 - 51 = 21
- Step 3: Find value of the expression for y = 3
⇒ ⇒ 6y² - 24y - 51 = 6(3)² - 24(3) - 51 = 54 - 72 - 51 = -69
14 beacause your multiplying 7x2 wich is 14
It’s a flip of the graph on the x-axis
Therefore f(x) = - x^2 (NOT IN PARENTHESIS that would be a reflection on the y axis)
It’s a shift 4 y values down therefore
g(x) = - x^2 - 4
