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larisa86 [58]
3 years ago
9

Four times a number added to 3 times a larger number is 31. Seven subtracted from the larger number is equal to twice the smalle

r number. Let x represent the smaller number and y represent the larger number. Which equations represent this situation? y = negative four-thirds x + 31. y = 2 x + 7. y = negative four-thirds x + StartFraction 31 Over 3 EndFraction. Y = 2 x + 7. y = negative four-thirds x + 31. y = negative 2 x + 7. y = negative four-thirds x + StartFraction 31 Over 3 EndFraction. Y = negative 2 x + 7.
Mathematics
1 answer:
notka56 [123]3 years ago
7 0

Answer:

Let x represent the smaller number and y represent the larger number

<u>For the first equation </u>

Four times a number added to 3 times a larger number is 31 is written as

4x + 3y = 31

Making y the subject we have

3y = - 4x + 31

Divide both sides by 3

That's

y =  -  \frac{4}{3} x +  \frac{31}{3}

<u>For the second equation</u>

Seven subtracted from the larger number is equal to twice the smaller number is written as

y - 7 = 2x

Making y the subject

We have

<h3>y = 2x + 7</h3>

Hope this helps you

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