<span>It appears to be a scalene triangle because its 3 sides are of different lengths</span>
P = 2(L + W)
P = 36
36 = 2(L + W)
36/2 = L + W
18 = L + W....L = 18 - W
A = L * W
A = 65
L = 18 - W
65 = W(18 - W)
65 = 18W - W^2
W^2 - 18W + 65 = 0
(W - 13)(W - 5) = 0
W - 13 = 0 .....L = 18 - 13
W = 13 L = 5
W - 5 = 0 L = 18 - 5
W = 5 L = 13
Not exactly sure which (length or width)...but one is 13 ft and the other is 5 ft
Answer:
The measure of ∠EFG is 52°
Step-by-step explanation:
Given line m is parallel to line p. m∠HEF = 39º and m∠IGF = 13º.we have to find m∠EFG.
In ΔJFG,
By angle sum property of triangle, which states that sum of all angles of triangle is 180°
m∠FJG+m∠JGF+m∠JFG=180°
⇒ 39°+13°+m∠JFG=180°
⇒ m∠JFG=180°-39°-13°=128°
As JFE is a straight line ∴ ∠JFG and ∠EFG forms linear pair
⇒ m∠JFG+m∠EFG=180°
⇒ 128°+m∠EFG=180°
⇒ m∠EFG=52°
The measure of ∠EFG is 52°
Given that:
f(x) = -2x²-2x+10
f(2) = -2(2)²-2(2)+10
= -2(2*2) - 4 + 10
= -2(4) - 4 + 10
= -8 - 4 + 10
= -12 + 10
= -2 Ans.
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