Ok, here we go:
5 cars total.
1. Rachel - first car in line, yellow, SUV
2. blue car (Rachel is in front of the blue car), convertible, Anton
3. minivan - third car in line, Diego
4. white car, sedan, Ingrid
5. green car, immediately behind white car, Yuna, pickup
We know that Rachel is first, a blue car is second and the minivan is third. We know that 3, 4 cannot be a convertible since one is a minivan and the other is a sedan. We also know that a yellow car is in front of the convertible.
Based off of that we know that car 5 cannot be a convertible since 4 is white and not yellow. So 1 or 2 is the convertible and SUV. But we know that Rachel is in front of a blue car and the yellow car is in front of a convertible so that makes car #2 the blue convertible and car #1 the yellow SUV.
Fill in what you do know and start to eliminate the outliers. Hope that helps.
Yes, they are equivalent. Another equivalent fraction would be any fraction that equals to 1. Eg. 9/9
Answer:
B
Step-by-step explanation:
Just take all three numbers (954, 158, 63) then add them all up.
I thin the answer is 8,9785
Answer:
2x + y = 12 & x = 9 - 2y --- (x = 5, y = 2)
x + 3y = 16 & 2x - y = 11 --- (x = 7, y = 3)
y = 11 - 2x & 4x - 3y = -13 --- (x = 2, y = 7)
2x + y = 11 & x - 2y = -7 --- (x = 3, y = 5)
Step-by-step explanation: