Question

Simply by applying distributive property and then multiplication property of square roots -√5(2-√5)

Answer 1

Solving $-\sqrt{5}(2-\sqrt{5})$ we get: $-2\sqrt{5}-5$

Step-by-step explanation:

We need to simplify $-\sqrt{5}(2-\sqrt{5})$ by applying distributive property and then multiplication property of square roots.

Solving:

Applying distributive property: a(b-c)= ab-ac

$-\sqrt{5}(2-\sqrt{5})\\=-\sqrt{5}*2-(-\sqrt{5}*\sqrt{5})\\=-2\sqrt{5}+(\sqrt{5}*\sqrt{5})$

Applying multiplication property of square roots:

$\sqrt{a}.\sqrt{a}=a\\so,\,\,\sqrt{5}.\sqrt{5}=5$

$=-2\sqrt{5}+(5)\\=-2\sqrt{5}+5$

So, Solving $-\sqrt{5}(2-\sqrt{5})$ we get: $-2\sqrt{5}+5$

Keywords: Solving square roots

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