What equation represents a line that passes through (2,-1/2) and has a slope of 3?

mariarad [96]

You don't need expedite and you don't need urgency.
All you need is the formula for the volume of a sphere.

==> Volume of a sphere = (4/3) (pi) (radius)³ .

The question gave you the radius, and told you what to use
for 'pi', so now you have all the information you need.

4 0

4 years ago

£ 5.4.3 Quiz A medical company tested a new drug on 100 people for possible side effects. This table shows the results. Side eff

Nimfa-mama [501]

Answer:

fifteen seconds after that one of my friend did a few days wale and then a

7 0

3 years ago

The Toylot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A) under a norma

kotegsom [21]

Answer:

Test statistic = 3.1587

Step-by-step explanation:

We are given that the Toy-lot company makes an electric train with a motor that it claims will draw an average of only 0.8 ampere (A).

Also, a sample of eleven motors was tested, and it was found that the mean current was x = 1.20 A, with a sample standard deviation of s = 0.42 A.

So, Null Hypothesis, $H_0$ : $\mu$ = 0.8 { claim of 0.8 A is not low}

Alternate Hypothesis, $H_1$ : $\mu$ > 0.8 { claim of 0.8 A is too low}

Now, the test statistics used here will be;

T.S. = $\frac{Xbar - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, X bar = sample mean = 1.20 A

s = sample standard deviation = 0.42 A

n = sample size = 11 motors

So, Test statistics = $\frac{1.20 - 0.8}{\frac{0.42}{\sqrt{11} } }$ ~ $t_1_0$

= 3.1587

At 1% level of significance, t table gives a critical value of 2.764 at 10 degree of freedom. Since our test statistics is higher than the critical value so we have sufficient evidence to reject null hypothesis .

Therefore, we conclude that Toy-lot claim of 0.8 A is too low.

8 0

4 years ago

A particle moves in a straight line so that its velocity at time

riadik2000 [5.3K]

Answer:

s(2) = 7.75

Step-by-step explanation:

given the velocity v(t) = t^3

we can find the position s(t) by simply integrating v(t) and using the boundary conditions s(1)=2

$s(t) = \int {v(t)} \, dt\\ s(t) = \int {t^3} \, dt\\s(t) = \dfrac{t^4}{4}+c$

we know throught s(1) = 2, that at t=1, s =2. we can use this to find the value of the constant c.

$s(1) = \dfrac{1^4}{4}+c\\4 = \dfrac{1^4}{4}+c\\c = 4-\dfrac{1}{4}\\c = \dfrac{15}{4} = 3.75$

Now we can use this value of t to formulate the position function s(t):

$s(t) = \dfrac{t^4}{4}+\dfrac{15}{4}\\$

this is the position at time t.

to find the position at t=2

$s(2) = \dfrac{2^4}{4}+\dfrac{15}{4}\\$

$s(2) = \dfrac{31}{4} = 7.75$

the position of the particle at time, t =2 is s(2) = 7.75

3 0

3 years ago

Steve works between 30 and 40 hours per week. The function f, where f(x)= 8.5x represents the amount of money Steve ears given t

Bess [88]

Answer: d) 255 ≤ f(x) ≤ 340

Step-by-step explanation:

The function

f(x)= 8.5x

represents the amount of money that Steve earns given the number of hours, x, he works.

The dependent variable is the total amount that he earns, f(x) while the independent variable is the number if hours, x that he works. The range is the possible values of the dependent variable that satisfies the equation.

Steve works between 30 and 40 hours per week. This means that

the lowest amount that he earns is 8.5×30 = $255

The highest amount that he earns is 8.5× 40 = 340. Therefore, the range is

255 ≤ f(x) ≤ 340

4 0

3 years ago