Answer:
Step-by-step explanation:
Given is a function as 
Equating to 0 we have equation
If the function f(x) has x intercepts then the solutions are real
Let us use remainder theorem and change of signs rule
f(0) = 1>0
f(-1) = -1+3+1=3
f(-2) = -32+6+1<0
This implies there is a real root between -1 and -2.
f(1) = -1
Since f(0) and f(1) have different signs, there exists a real root between 0 and 1.
f(2) = 32-6+1>0
Since f(1) and f(2) have different signs there exists a real root between 1 and 2.
Thus there are definitely three real solutions as
one between -1 and 0, one between 0 and 1, and third between 1 and 2.
Answer:
one: 9
Two: D
Step-by-step explanation:
One
The symbol used is x≥8 so 8 is included in the function part. That would mean that F(x) = 9
Two
The value you need to use is -4x + 3. That's because -2≤x and the symbol ≤ makes - 2 inclusive.
-4(-2) + 3 = 8 + 3 = 11
3a
The function is decreasing over -4x + 3
It goes from 11 to -29 roughly. That means it's going from a positive to negative number. Definitely decreasing
3b
The function is a constant when x≥8. The value of the function is 9 no matter what x is.
3c
The function is increasing from - 2x to 8 which is going from -9 to 11
Answer:
B
Step-by-step explanation:
(x - 4) because a = x and b = 4, subsitute into (a - b)
(x2 + 4x + 16) because if a = x and b = 4, you subsitute them into (a2 + ab + b2) to get your answer
If you want to find a fraction of something, multiply that amount by the fraction.
So to find 1/3 of 3/5, multiply the two fractions together
(3/5) (1/3) = 3/15 or 1/5
So 1/3 of 3/5 is 3/15, or if you simply it, 1/5
The answer is 1 1/15
You just add 7 and 9, then you get 16
16/15 is 1 and 1/15
