All categories

3 years ago

Please help ! Graph ; Y= 3= 1/2 (x+3)

Mathematics

2 answers:

Paraphin [41]3 years ago

8 0

Answer mine!

Step-by-step explanation:

Answer my question to please!!

Lelu [443]3 years ago

3 0

Answer:

See picture.

Step-by-step explanation:

This line is in point slope form $y - y_1 = m(x-x_1)$ where $(x_1, y_1)$ is a point on the line. Begin graphing the line by first graphing the point (-3, 3) from the equation. Then move up 1 unit and over 2 units according to slope. This new point is (-1,4).

You might be interested in

the baker's at healthy Bakery can make 230 Bagels in 2 hours how many bagels can they bake in 19 hours what was that rate per ho

dybincka [34]

115 will be the (unit) rate :]

8 0

3 years ago

If two sides of a triangle are 9cm and 15cm in length, which COULD be the measure of the third side?

MArishka [77]

The lemght could be 15 because a triangle has two long sides and one short one and the two are equivalent

5 0

3 years ago

A client asks your catering company to provide a quote on a three-course dinner for 100 people. You know that it will cost you $

marissa [1.9K]

Sorry I don’t know that one

5 0

3 years ago

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

3 years ago

Read 2 more answers

Solve each equation -8a - 1=-23

bagirrra123 [75]

-8a/8 = 22

8 divided by 22 is 2.75

a = -2.75

5 0

3 years ago

Read 2 more answers