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sesenic [268]
4 years ago
5

What's the value of the underlined digit 3 6,035

Mathematics
2 answers:
andrezito [222]4 years ago
4 0
Because the 3 is in the tens place, the value is equal to
3*10
30

Final answer: 30
m_a_m_a [10]4 years ago
3 0
Hello, if "3" your 'underlined digit" then you're answer would be: the 3 is in the "tens " place

Good luck!
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Cody was looking at his streaming music stats. The Ratio of songs he liked to disliked was 5:6. If he listened to 1,078 songs to
aivan3 [116]
1078 / (5+6) = 98
Like - 5 x 98 = 490
Dislike - 6 x 98 = 588
6 0
3 years ago
In the graph shown, suppose that f(x) = 3.5x and h(x) = 1.5x. Choose the statement that COULD be true.
faust18 [17]

Answer: D

Step-by-step explanation:

The given functions are

Now these are exponential curves and the bases for the functions are 3.5 & 1.5

Also the graph of g(x) is between f(x) & h(x)

Hence the value of base called the scale factor must be between 3.5 & 1.5.

4 & 5 are more than 3.5

0.9 is smaller than 1.5

But π = 3.14 lies between 3.5 & 1.5.

Hence the only option which can represent the graph of g(x) is

Option D) is the right answer

3 0
3 years ago
What number is 15% of 80?<br> use percent proportions
vova2212 [387]
!5% is equivalent to 15 parts over the whole 100 part. It is written in proportions as 15/100. 

Similarly, you need to find how many parts in 80 are equivalent to 15%or 15/100. So, just equate both equation with x as an unknown.

x/80 = 15/100
x = (15/100)*80
x = 12

Thus, the 15% of 80 is 12.
8 0
3 years ago
Given that cot θ = 1/√5, what is the value of (sec²θ - cosec²θ)/(sec²θ + cosec²θ) ?
Bogdan [553]

Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{{sec}\theta = \dfrac{1}{cos\theta}}}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

\mathsf{\implies \dfrac{\dfrac{1}{cos^2\theta} - \dfrac{1}{sin^2\theta}}{\dfrac{1}{cos^2\theta} + \dfrac{1}{sin^2\theta}}}

\mathsf{\implies \dfrac{\dfrac{sin^2\theta - cos^2\theta}{sin^2\theta.cos^2\theta}}{\dfrac{sin^2\theta + cos^2\theta}{sin^2\theta.cos^2\theta}}}

\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

\mathsf{\implies \dfrac{sin^2\theta\left(1 - \dfrac{cos^2\theta}{sin^2\theta}\right)}{sin^2\theta\left(1 + \dfrac{cos^2\theta}{sin^2\theta}\right)}}

\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{cot\theta = \dfrac{cos\theta}{sin\theta}}}}

\mathsf{\implies \dfrac{1 -cot^2\theta}{1 + cot^2\theta}}

\mathsf{Given :\;cot\theta = \dfrac{1}{\sqrt{5}}}

\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

<u>Hence</u><u>,</u><u> option</u><u> </u><u>(</u><u>a)</u><u> </u><u>2</u><u>/</u><u>3</u><u> </u><u>is </u><u>your</u><u> </u><u>correct</u><u> </u><u>answer</u><u>.</u>

3 0
3 years ago
Expand (3x-4y)^3 please answer thank you
WARRIOR [948]
27x^3-108x^2y+144xy^2-64y^3
5 0
4 years ago
Read 2 more answers
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