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anzhelika [568]
3 years ago
7

Use the change of base formula to evaluate log3(73).

Mathematics
1 answer:
Marrrta [24]3 years ago
3 0
The change of base formula allows you to write a logarithm in terms of logarithms with another base. It follows this pattern,

log_{a}x =  \frac{ log_{b}x }{log_{b}a }

where a≠1 and b≠1

Assigning the base to be 7,

log_{3}73 = \frac{ log_{7}73 }{log_{7}3 }=3.9


I hope I was able to answer your question. Have a good day.
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Answer:

x = 3 , y = 13

Step-by-step explanation:

Note that both equations is equal to y. Set the two equations equal to each other

y = 7x - 8; y = 5x - 2

7x - 8 = y = 5x - 2

7x - 8 = 5x - 2

Isolate the x. Subtract 5x and add 8 to both sides

7x (-5x) - 8 (+8) = 5x (-5x) - 2 (+8)

7x - 5x = -2 + 8

Simplify.

(7x - 5x) = (-2 + 8)

2x = 6

Isolate the x. Divide 2 from both sides

(2x)/2 = (6)/2

x = 6/2

x = 3

---------------------------------------------------------------------------------------------------

Plug in 3 for x in one of the equations.

y = 7x - 8

y = 7(3) - 8

Simplify. Remember to follow PEMDAS.

y = 7(3) - 8

y = 21 - 8

y = 13

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x = 3, y = 13 is your answer

~

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