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3 years ago

If w=the weight of a trout, which algebraic expression represents the phrase below?

Mathematics

1 answer:

ivann1987 [24]3 years ago

6 0

Answer:

Step-by-step explanation:

The only option with multiplication represented is A.

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Y is less than or equal to -1

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3 years ago

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Finn is allowed to watch TV for 30 minutes every day. Sloane is allowed to watch 4 times as much TV a day. How much TV can Sloan

chubhunter [2.5K]

Answer:

hscuhfeehfjhjhfj

Step-by-step explanation:

ehfjehfjefhjefh

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3 years ago

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What is the following simplified product? Assume x greater-than-or-equal-to 0 2 StartRoot 8 x cubed EndRoot (3 StartRoot 10 x Su

dalvyx [7]

The simplified expression of 2√8x³(3√10x⁴ - x√5x²) is 24x³√5x - 4x³√10x

<h3>How to determine the simplified product?</h3>

The complete question is added as an attachment

From the attached figure, the product expression is:

2√8x³(3√10x⁴ - x√5x²)

Evaluate the exponents

2√8x³(3√10x⁴ - x√5x²) = 2 *2x√2x(3x²√10 - x²√5)

Evaluate the products

2√8x³(3√10x⁴ - x√5x²) = 4x√2x(3x²√10 - x²√5)

Open the bracket

2√8x³(3√10x⁴ - x√5x²) = 12x³√20x - 4x³√10x

Evaluate the exponents

2√8x³(3√10x⁴ - x√5x²) = 24x³√5x - 4x³√10x

Hence, the simplified expression of 2√8x³(3√10x⁴ - x√5x²) is 24x³√5x - 4x³√10x

Read more about expressions at:

brainly.com/question/12990602

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2 years ago

If you bought a stock last year for a price of $147, and it has risen 17.9% since then, how much is the stock worth now, to the

zysi [14]

Answer:

This is an percentage question, meaning you have to calculate the percentage rise.

1) Do 147 * 17.9% (Which equals to 26.3 [1.d.p.])

2) 26.3 is the answer

Hope it helps! :D

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3 years ago

Scores on a university exam are Normally distributed with a mean of 78 and a standard deviation of 8. The professor teaching the

mafiozo [28]

Answer:

Porcentage of students score below 62 is close to 0,08%

Step-by-step explanation:

The rule

68-95-99.7

establishes:

The intervals:

[ μ₀ - 0,5σ , μ₀ + 0,5σ] contains 68.3 % of all the values of the population

[ μ₀ - σ , μ₀ + σ] contains 95.4 % of all the values of the population

[ μ₀ - 1,5σ , μ₀ + 1,5σ] contains 99.7 % of all the values of the population

In our case such intervals become

[ μ₀ - 0,5σ , μ₀ + 0,5σ] ⇒ [ 78 - (0,5)*8 , 78 + (0,5)*8 ] ⇒[ 74 , 82]

[ μ₀ - σ , μ₀ + σ] ⇒ [ 78 - 8 , 78 +8 ] ⇒ [ 70 , 86 ]

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 78 - 12 , 78 + 12 ] ⇒ [ 66 , 90 ]

Therefore the last interval

[ μ₀ - 1,5σ , μ₀ + 1,5 σ] ⇒ [ 66 , 90 ]

has as lower limit 66 and contains 99.7 % of population, according to that the porcentage of students score below 62 is very small, minor than 0,15 %

100 - 99,7 = 0,3 %

Only 0,3 % of population is out of μ₀ ± 1,5 σ, and by symmetry 0,3 /2 = 0,15 % is below the lower limit, 62 is even far from 66 so we can estimate, that the porcentage of students score below 62 is under 0,08 %

6 0

3 years ago